Question

A uniformly charged disk of radius 35.0 cm carries a charge density of 6.40 ✕ 10^-3 C/m². Calculate the electric field on the axis of the disk at the following distances from the center of the disk.

(a) 5.00 cm
MN/C

(b) 10.0 cm
MN/C

(c) 50.0 cm
MN/C

(d) 200 cm
MN/C

Answer 1

The electric field due to a uniformly charged disk is given by

Where

k is the coulomb's constant,

is the charge density

R is the radius of the disk and

x is the distance of the point of the interest on the axis of the disk from the center of the disk.

Now putting all the values in SI units

PART A:

So, the electric field at 5 cm from the center of the disk is 310.73 MN/C.

PART B:

So, the electric field at 5 cm from the center of the disk is 262.49 MN/C.

PART C:

So, the electric field at 5 cm from the center of the disk is 65.42 MN/C.

PART D:

So, the electric field at 5 cm from the center of the disk is 5.42 MN/C.