In: Statistics and Probability
1. M 644
2. F 345
3. F 710
4. F 655
5. F 539
6. M 492
7. M 598
8. F 481
9. F 622
10. F 545
11. M 707
12. F 332
13. M 538
14. F 470
15. M 469
16. F 483
17. M 572
18. F 487
19. M 358
20. F 440
21. F 637
22. M 447
23. F 482
24. M 485
25. F 417
26. M 569
27. M 541
28. F 596
29. F 395
30. M 526
31. M 643
32. M 435
33. F 511
34. F 766
35. F 467
36. F 562
37. M 460
38. M 483
39. F 644
40. F 606
The first task you have is to select a sample of 40 students. Carefully explain your procedure and reasoning for selecting these 40 students. Use your sample to describe the high school’s performance as a whole. Produce the proper statistical summaries and graphs.
Next, use your sample to create a 95% confidence interval for the mean SAT math score at this high school. Interpret the interval. Based on your confidence interval, compare the performance of these students with the statewide mean math score of 503.
Your last portion of the project is to address this following question. Nationally males tend to have higher Math scores than Females. Use the sample to determine if that is true at this high school. Be sure to check all assumptions and conditions when determining the answer to this question.
95% CONFIDENCE INTERVAL IS
sample mean = 528.98
t critical = 2.02
sM = √(101.561^2/40) = 16.06
μ = M ± t(sM)
μ = 528.98 ± 2.02*16.06
μ = 528.98 ± 32.4808
95% CI [496.4992, 561.4608].
You can be 95% confident that the population mean (μ) falls between 496.4992 and 561.4608.
Since statewide wide mean math score is in the 95% confidence interval therefore the performance of randomly selected 40 students math score is NOT different from 503 score.
NULL HYPOTHESIS H0:
ALTERNATIVE HYPOTHESIS Ha:
To conduct this test we will check the following assumption:
1) Random sample is normally distributed.
2) Population variances are equal.
From above table we can see that Equal variance assumption is satisfied. Since P value from Levene's test is 0.248>0.05 THEREFORE WE FAIL TO REJECT NULL HYPOTHESIS H0 THEREFORE VARIANCES ARE EQUAL.
t value = -0.08
Degrees of freedom=38
The P-Value is .468329. The result is not significant because p > .05.
Decision: Fail to reject null hypothesis H0.
Conclusion: We dont have sufficient evidence to show that males tend to have higher Math scores than Females.