In: Statistics and Probability
7. This scenario can be modeled as a
(a) normal experiment with 4 trials and success probability of 1/6 per trial.
(b) normal experiment with 6 trials and success probability of 1/4 per trial.
(c) binomial experiment with 6 trials and success probability of 1/5 per trial.
(d) binomial experiment with 4 trials and success probability of 1/6 per trial.
(e) binomial experiment with 6 trials and success probability of 1/4 per trial.
8. Complete the following table that represents the probability distribution of
X
= the number of
questions Han guesses correctly.
x
0
1
2
3
4
5
6
P(X = x)
(a) 1/7, 2/7, 3/7, 4/7, 5/7, 6/7, 1
(b) .1780, .5339, .8306, .9624, .9954, .9996, 1
(c) 1/7, 1/7, 1/7, 1/7, 1/7, 1/7, 1/7
(d) .1780, .3560, .2966, .1318, .0330, .0044, .0002
(e) 1/6, 1/6, 1/6, 1/6, 1/6, 1/6
9. What is the probability he will answer at least 4 of the questions correctly?
(a) 0.0376 (b) 10/12 (c) .67% (d) 2/12 (e) 0.0046
10. What is the mean number of questions he will answer correctly?
(a) 0 (b) 1 (c) 1.5 (d) 2 (e) 4
11. What is the standard deviation of the number of questions he will answer correctly?
(a) 0.46 (b) 1 (c) 1.06 (d) 1.5 (e) 1.6
7) (e) binomial experiment with 6 trials and success probability of 1/4 per trial.
8) (d) ( look the below excel-sheet )
9) a)
P(X >= 4) = 0.0330+0.0044+0.0002 = 0.0376
10) (c)
11) (c)
The formulae used on the above excel-sheet are as follow: