In: Statistics and Probability
A sample of size 41 will be drawn from a population with mean 20 and standard
deviation 13. Find the probability that x will be less than 23.
Solution :
Given that mean μ = 20, standard deviation σ = 13, n = 41
=> P(x < 23) = P((x -μ)/(σ/sqrt(n)) < (23 - 20)/(13/sqrt(41)))
= P(Z < 1.4776)
= 0.9306