Question

A previous semester's set of data from the initial questionnaire results in the following frequency table (some minor adjustments were made).

Eye color	+8 hours of sleep	<8 hours of sleep
Brown	6	7
Blue	4	1
Other	1	3

(a) If the possibilities for eye color are brown (Br), blue (Bl), and other (O), and the possibilities for sleep are at least 8 hours (Y) and less than 8 hours (N), one possible outcome for eye color and sleep after choosing a student is "BrY" (brown eyes and slept at least 8 hours). List one other possible outcome:  

(b) What is the probability of the event "has blue eyes" occurring if a student is chosen at random? State your answer as a fraction (e.g. "3/7")   

(c) What is the probability of someone having brown eyes OR getting +8 hours of sleep? State your answer as a fraction (e.g. "3/7")

(d) In how many ways can you get exactly two people who have <8 hours of sleep?   

(e) Suppose two different students are chosen at random. What is the probability that both students have brown eyes? State your answer to two decimal places.

(f) Suppose one student is chosen at random. What is the probability that the student has an "other" eye color given that they got less than 8 hours of sleep? Give your answer as a fraction (e.g. "3/7").

(g) In how many different ways can you choose 3 different people at random out of the entire group of students? State your answer to two decimal places.    

Answer 1