Question

In: Statistics and Probability

A marketing professor at Givens College is interested in the relationship between hours spent studying and...

A marketing professor at Givens College is interested in the relationship between hours spent studying and total points earned in a course. Data collected on 10 students who took the course last quarter follow.

Hours
Spent Studying
Total
Points Earned
45 40
30 35
90 75
60 65
105 90
65 50
90 90
80 80
55 45
75 65

(a)

Develop an estimated regression equation showing how total points earned can be predicted from hours spent studying. (Round your numerical values to two decimal places.)

ŷ =

(b)

Test the significance of the model with α = 0.05. (Use the F test.)

State the null and alternative hypotheses.

H0: β1 = 0
Ha: β1 ≠ 0

H0: β0 = 0
Ha: β0 ≠ 0    

H0: β0 ≠ 0
Ha: β0 = 0

H0: β1 ≠ 0
Ha: β1 = 0

H0: β1 ≥ 0
Ha: β1 < 0

Find the value of the test statistic. (Round your answer to two decimal places.)

________

Find the p-value. (Round your answer to three decimal places.)

p-value = ______

State your conclusion.

Reject H0. We cannot conclude that the relationship between hours spent studying and total points earned is significant.

Reject H0. We conclude that the relationship between hours spent studying and total points earned is significant.     

Do not reject H0. We conclude that the relationship between hours spent studying and total points earned is significant.

Do not reject H0. We cannot conclude that the relationship between hours spent studying and total points earned is significant.

(c)

Predict the total points earned by Mark Sweeney. He spent 70 hours studying. (Round your answer to two decimal places.)

__________ points

(d)

Develop a 95% prediction interval for the total points earned by Mark Sweeney. (Round your answers to two decimal places.)

______points to _____points

Solutions

Expert Solution

Conlusion:

Reject H0. We conclude that the relationship between hours spent studying and total points earned is significant.     

Ansc:

y^ when x=70

Y^=5.8470+(0.8295)*x

y^=5.8470+(0.8295*70)

y^=63.912


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