Question

In: Statistics and Probability

A CI is desired for the true average stray-load loss μ (watts) for a certain type...

A CI is desired for the true average stray-load loss μ (watts) for a certain type of induction motor when the line current is held at 10 amps for a speed of 1500 rpm. Assume that stray-load loss is normally distributed with σ = 3.3. (Round your answers to two decimal places.)

(a) Compute a 95% CI for μ when n = 25 and x = 54.7.

(      ,        )   watts

(b) Compute a 95% CI for μ when n = 100 and x = 54.7.

(        ,     ) watts
(c) Compute a 99% CI for μ when n = 100 and x = 54.7

(          ,         ) watts
(d) Compute an 82% CI for μ when n = 100 and x = 54.7.

(          ,          ) watts
(e) How large must n be if the width of the 99% interval for μ is to be 1.0? (Round your answer up to the nearest whole number.)
n =


You may need to use the appropriate table in the Appendix of Tables to answer this question.

Solutions

Expert Solution

For normally distributed population with population standard deviation given, Confidence interval is given by,

Given,

a) 95% Confidence interval,

, n=25

Z-value for 95% confidence is 1.96

(53.41, 55.99)

b) 95% confidence interval,

, n=100

Z-value for 95% confidence is 1.96

( 54.05, 55.35)

c) 99% confidence interval,

, n=100

Z-value for 99% confidence is 2.58

( 53.85, 55.55)

d) 82% confidence interval,

, n=100

Z value for 82% confidence is 1.34

(54.26, 55.14)

e) 99% confidence, with  width =1

Total width=1, which means each tail would be 0.5

Z-value for 99% confidence is 2.58


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