In: Statistics and Probability
Several turns later you end up in jail (in the game): the rules says that on your turn if you roll a six-sided die three times without getting a 1 you get out of jail. What is the probability that you will not get out of jail on your next turn, i.e. what is the probability that you roll a one at least once in three rolls?
P(getting 1 in single die) = 1/6
P(not getting 1 in three times) = (1 - 1/6)3 = 0.5787
P(you will not get out of jail on your next turn) = P(rolling a 1 at least once in three rolls)
= 1 - P(not getting 1 in three times)
= 1 - 0.5787
= 0.4213