In: Physics
When an AC source is connected across a 11.5-? resistor, the rms current in the resistor is 8.66 A.
(a) Find the rms voltage across the resistor.
V
(b) Find the peak voltage of the source.
V
(c) Find the maximum current in the resistor.
A
(d) Find the average power delivered to the resistor.
W
a). rms voltage across the resistor Vrms = Irms R
= 8.66 11.5
= 99.59 Volts
rms voltage across the resistor Vrms = 99.59 Volts
b).Peak voltage source Vpeak = Vrms 2
= 99.59 2
= 140.841 volts
Peak voltage of the source Vpeak = 140.841 Volts
c). Maximum current in the resistor Imax = Irms2
= 8.66 2
= 12.247 amps
Maximum current in the resistor Imax = 12.247 amps
d). Average power delivered to the resistor Pavg = Vrms Irms
= 140.841 12.247
= 1724.892 watts
Average power delivered to the resistor Pavg = 1724.892 watts