Question

A -14 nC charge is located at the origin. What is the strength of the electric field at the position (x,y)=(0cm,5.0cm)? What is the strength of the electric field at the position (x,y)=(−5.0cm,−5.0cm)? What is the strength of the electric field at the position (x,y)=(−5.0cm,5.0cm)?

Answer 1

(A) E = KQ/r^2 = (9 x 10^9 x 14 x 10^-9) / (.05)^2 = 50400 N/C

(B) r = sqrt (5^2 + 5^2) = 5√2 = 5 x 1.41 = 7.07 cm = .0707 m

E = KQ/r^2 = (9 x 10^9 x 14 x 10^-9) / (.0707)^2 = 25207.61 N/C

(C) r = √(5^2 + 5^2) = 7.07 cm = ,0707 m

E = KQ/r^2 = (9 x 10^9 x 14 x 10^-9) / (.0707)^2 = 25207.61 N/C