In: Accounting
Let the number of units of MV cable to be manufactured be X and of LV Cables be Y.
Now, we need to maximize the profit.
The Objective function will be
Maximize Z = 200X + 350Y
Since, the number of cables maufactured cannot be negative, we will also have non-negative variable constraints: -
X, Y >=0
Here, the constraints are production hours, skilled labour hours and material units and can be be expresses mathematically as: -
For production hours -
5X + 3Y <= 180 ....... equation (i)
For Skilled Labour Hours -
5X + 6Y <= 240 ....... equation (iI)
For material -
2X + 2Y <= 100
2(X + Y) <= 100
X + Y <= 50
Demand constraint
X >= 30
Y >= 10
Now, plotting equation (i) & (ii) and non negative constraint on graph and shading the region which satisfies the equation we get 4 different corner points and then using those corner points in maximizing equation we get our optimum product mix which is as under:
MV Cable = 0
LV Cable = 40
Maximum contribution = 40 X 350 = RO 14000
The graph and calculation of points on graph is attached.