In: Physics
A projectile is shot straight up from the earth's surface at a speed of 5000km/hr .
How high does it go?
Express your answer with the appropriate units.
The acceleration due to gravity is -9.8m/s^2. Convert 5000km/h
to m/s by dividing by 3.6 to get 1388.8 repeating.
Now use the formula vf^2 = vi^2 + 2ad and solve for d. The final
velocity is 0 because that is where it is at its highest point.
This formula works because it is independent of (doesn't have)
time. So,
(vf^2-vi^2)/2a = d
(0km/h^2 - 1388.8m/s^2)/2(-9.8m/s^2) = d
-1929012.2m^2/s^2)/-19.6m/... = d
d = 98418m