A projectile is shot straight up from the earth's surface at a speed of 5000km/hr ....

A projectile is shot straight up from the earth's surface at a speed of 5000km/hr .

How high does it go?

Express your answer with the appropriate units.

Solutions

Expert Solution

The acceleration due to gravity is -9.8m/s^2. Convert 5000km/h to m/s by dividing by 3.6 to get 1388.8 repeating.
Now use the formula vf^2 = vi^2 + 2ad and solve for d. The final velocity is 0 because that is where it is at its highest point. This formula works because it is independent of (doesn't have) time. So,

(vf^2-vi^2)/2a = d

(0km/h^2 - 1388.8m/s^2)/2(-9.8m/s^2) = d

-1929012.2m^2/s^2)/-19.6m/... = d

d = 98418m

genius_generous answered 1 year ago

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