In: Statistics and Probability
Three different states participate in a poll of attitudes toward two possible energy policies(Policy I, and Policy II . The results are given in the table below:
State
policy choice Gas Coal Other
I 50 59 161 II 80 71 129
To test the null of association (Independence) between the type of the state and the policy choice. Use ALPHA=.01, then (
A) Test Stat: LaTeX: \chi χ 2 LaTeX: \approx ≈ 10.384 ; p-vLaTeX: \approx ≈ .009 ; Dec: Reject the null
(B) Test Stat: LaTeX: \chi χ 2 LaTeX: \approx ≈ 11.384 ; p-v LaTeX: \approx ≈ .003 ; Dec: Reject the null
(C) Test Stat : LaTeX: \chi χ 2 LaTeX: \approx ≈ 11.384 ; p-v LaTeX: \approx ≈ .030 ; Dec: Reject the null
From the given information,
By using chi-square test of the Independence calculator,
Hence,
Test Stat: LaTeX: \chi χ 2 LaTeX: \approx ≈ 11.384 ; p-v LaTeX: \approx ≈ .003 ; Dec: Reject the null
i.e., Option B. is correct.
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