Question
In: Statistics and Probability
Individual Bettendorf Salary Experience (X1) Education (X2) Sex (X3) 1 53600 5.5 4.0 F 2 52500...
| Individual | Bettendorf Salary | Experience (X1) | Education (X2) | Sex (X3) |
| 1 | 53600 | 5.5 | 4.0 | F |
| 2 | 52500 | 9.0 | 4.0 | M |
| 3 | 58900 | 4.0 | 5.0 | F |
| 4 | 59000 | 8.0 | 4.0 | M |
| 5 | 57500 | 9.5 | 5.0 | M |
| 6 | 55500 | 3.0 | 4.0 | F |
| 7 | 56000 | 7.0 | 3.0 | F |
| 8 | 52700 | 1.5 | 4.5 | F |
| 9 | 65000 | 8.5 | 5.0 | M |
| 10 | 60000 | 7.5 | 6.0 | F |
| 11 | 56000 | 9.5 | 2.0 | M |
| 12 | 54900 | 6.0 | 2.0 | F |
| 13 | 55000 | 2.5 | 4.0 | M |
| 14 | 60500 | 1.5 | 4.5 | M |
What is the “slope” of the linear relationship?
Select one:
a. 425
b. 223.0
c. 498.0
d. .305
2. What can you conclude about the relationship?
Select one:
a.
There is a strong negative relationship between the data.
b.
There is a weak positive relationship between the data.
c.
There is a strong positive relationship between the data.
d.
There is a weak negative relationship between the data.
Solutions
Expert Solution
What is the “slope” of the linear relationship?
b. 223.0
2. What can you conclude about the relationship?
b. There is a weak positive relationship between the data.
| r² | 0.036 | |||||
| r | 0.190 | |||||
| Std. Error | 3540.188 | |||||
| n | 14 | |||||
| k | 1 | |||||
| Dep. Var. | Bettendorf Salary | |||||
| ANOVA table | ||||||
| Source | SS | df | MS | F | p-value | |
| Regression | 56,17,003.7047 | 1 | 56,17,003.7047 | 0.45 | .5159 | |
| Residual | 15,03,95,139.1524 | 12 | 1,25,32,928.2627 | |||
| Total | 15,60,12,142.8571 | 13 | ||||
| Regression output | confidence interval | |||||
| variables | coefficients | std. error | t (df=12) | p-value | 95% lower | 95% upper |
| Intercept | 55,613.5041 | |||||
| Experience (X1) | 223.0234 | 333.1381 | 0.669 | .5159 | -502.8223 | 948.8691 |
orchestra answered 1 year agoRelated Solutions
Individual Bettendorf Experience (X1) Education (X2) Sex (X3) 1 53600 5.5 4 F 2 52500 9...
Individual
Bettendorf
Experience (X1)
Education (X2)
Sex (X3)
1
53600
5.5
4
F
2
52500
9
4
M
3
58900
4
5
F
4
59000
8
4
M
5
57500
9.5
5
M
6
55500
3
4
F
7
56000
7
3
F
8
52700
1.5
4.5
F
9
65000
8.5
5
M
10
60000
7.5
6
F
11
56000
9.5
2
M
12
54900
6
2
F
13
55000
2.5
4
M
14
60500
1.5
4.5
M
1. What...
Individual Bettendorf Experience (X1) Education (X2) Sex (X3) 1 53600 5.5 4 F 2 52500 9...
Individual
Bettendorf
Experience (X1)
Education (X2)
Sex (X3)
1
53600
5.5
4
F
2
52500
9
4
M
3
58900
4
5
F
4
59000
8
4
M
5
57500
9.5
5
M
6
55500
3
4
F
7
56000
7
3
F
8
52700
1.5
4.5
F
9
65000
8.5
5
M
10
60000
7.5
6
F
11
56000
9.5
2
M
12
54900
6
2
F
13
55000
2.5
4
M
14
60500
1.5
4.5
M
1. At...
Let X1, X2, X3 be continuous random variables with joint pdf f(X1, X2, X3)= 2 if...
Let X1, X2, X3 be continuous random variables with joint pdf
f(X1, X2, X3)= 2 if 1<X1<2 -1<X2<0
-X2-1<X3<0
0 otherwise
Find Cov(X2, X3)
(1) z=ln(x^2+y^2), y=e^x. find ∂z/∂x and dz/dx. (2) f(x1, x2, x3) = x1^2*x2+3sqrt(x3), x1 = sqrt(x3),...
(1) z=ln(x^2+y^2), y=e^x. find ∂z/∂x and dz/dx.
(2) f(x1, x2, x3) = x1^2*x2+3sqrt(x3), x1 = sqrt(x3), x2 = lnx3.
find ∂f/∂x3, and df/dx3.
3. Given is the function f : Df → R with F(x1, x2, x3) = x...
3. Given is the function f : Df → R with F(x1, x2, x3) = x 2 1 +
2x 2 2 + x 3 3 + x1 x3 − x2 + x2 √ x3 . (a) Determine the gradient
of function F at the point x 0 = (x 0 1 , x0 2 , x0 3 ) = (8, 2,
4). (b) Determine the directional derivative of function F at the
point x 0 in the direction given...
The prices of inputs (x1,x2,x3,x4) are (4,1,3,2): (a) If the production function is given by f(x3,x4)...
The prices of inputs (x1,x2,x3,x4) are
(4,1,3,2):
(a) If the production function is given by f(x3,x4)
=min{x1+x2,x3+x4} what is the minimum cost of producing one unit
of output?
(b) If the production function is given by
f(x3,x4)=x1+x2 +min{x3+x4} what is the minimum cost of producing
one unit of output?
The values of X1, X2, X3, X4 and X5 are .1, .2, .08, .2 and .3....
The values of X1, X2, X3, X4 and X5 are .1, .2, .08, .2 and .3.
Explicate the meaning of those numbers for the Z score. What are
the prospects of this firm? Discuss thoroughly.
Let X = ( X1, X2, X3, ,,,, Xn ) is iid, f(x, a, b) =...
Let X = ( X1, X2, X3, ,,,, Xn ) is iid,
f(x, a, b) = 1/ab * (x/a)^{(1-b)/b} 0 <= x <= a ,,,,, b
< 1
then, find a two dimensional sufficient statistic for (a, b)
4.Maximize: Z = 2X1+ X2-3X3 Subject to: 2X1+ X2= 14 X1+ X2+ X3≥6 X1, X2, X3≥0...
4.Maximize: Z = 2X1+ X2-3X3
Subject to: 2X1+ X2= 14
X1+ X2+ X3≥6
X1, X2, X3≥0
Solve the problem by using the M-technique.
(a) Consider three positive integers, x1, x2, x3, which satisfy the inequality below: x1 +x2 +x3...
(a) Consider three positive integers, x1, x2, x3, which satisfy
the inequality below: x1 +x2 +x3 =17. (1) Let’s assume each element
in the sample space (consisting of solution vectors (x1, x2, x3)
satisfying the above conditions) is equally likely to occur. For
example, we have equal chances to have (x1, x2, x3) = (1, 1, 15) or
(x1, x2, x3) = (1, 2, 14). What is the probability the events x1
+x2 ≤8occurs,i.e.,P(x1 +x2 ≤8|x1 +x2 +x3 =17andx1,x2,x3 ∈Z+)(Z+...
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