Question
In: Statistics and Probability
Company XYZ know that replacement times for the quartz time pieces it produces are normally distributed...
Company XYZ know that replacement times for the quartz time
pieces it produces are normally distributed with a mean of 15.4
years and a standard deviation of 1.8 years.
Find the probability that a randomly selected quartz time piece
will have a replacement time less than 9.8 years?
P(X < 9.8 years) = __________
Enter your answer accurate to 4 decimal places. Answers obtained
using exact z-scores or z-scores rounded to 3
decimal places are accepted.
If the company wants to provide a warranty so that only 2.5% of the
quartz time pieces will be replaced before the warranty expires,
what is the time length of the warranty?
warranty = ________ years
Enter your answer as a number accurate to 1 decimal place. Answers
obtained using exact z-scores or z-scores rounded
to 3 decimal places are accepted.
Solutions
orchestra answered 2 years agoRelated Solutions
Company XYZ know that replacement times for the DVD players it produces are normally distributed with...
Company XYZ know that replacement times for the DVD players it
produces are normally distributed with a mean of 4.7 years and a
standard deviation of 2.3 years.
Find the probability that a randomly selected DVD player will have
a replacement time less than -0.8 years?
P(X < -0.8 years) =
Enter your answer accurate to 4 decimal places. Answers obtained
using exact z-scores or z-scores rounded to 3
decimal places are accepted.
If the company wants to provide a...
Suppose that replacement times for washing machines are normally distributed with a mean of 9.3 and...
Suppose that replacement times for washing machines are normally
distributed with a mean of 9.3 and a standard deviation of 1.1
years. Find the probability that 70 randomly selected washing
machines will have a mean replacement time less than 9.1 years.
Replacement times for Timex watches are normally distributed with a mean of 10.2 years and a...
Replacement times for Timex watches are normally distributed
with a mean of 10.2 years and a standard deviation of 3.1 years
(Based on data from “Getting Things Fixed”, Consumer Reports).
a. What percentage of watches should last between 8 and 9
years?
b. At least how many years should the longest 25% of all watches
last?
c. If Timex wants to provide a warranty so that only 1% of the
watches will be replaced before the warranty expires, what is...
Replacement times for TV sets are normally distributed with a mean of 8.2 years and a...
Replacement times for TV sets are normally distributed with a
mean of 8.2 years and a standard deviation of 1.1 years. (Change
the final answer to a % and keep 2 decimal places) a)
Find the probability that a randomly selected TV set will have a
replacement time between 9.5 and 10.5 years. (Include diagram) b)
Find the probability that 35 randomly selected TV sets will have a
mean replacement time less than 8.0 years. (Include diagram)
4. Replacement times for TV sets are normally distributed with a mean of 8.2 years and...
4. Replacement times for TV sets are normally distributed with a
mean of 8.2 years and a standard deviation of 1.1 years. (Change
the final answer to a % and keep 2 decimal places) a)
Find the probability that a randomly selected TV set will have a
replacement time between 9.5 and 10.5 years. (Include diagram) b)
Find the probability that 35 randomly selected TV sets will have a
mean replacement time less than 8.0 years. (Include diagram)
Replacement time for TV sets are normally distributed with a mean of 7.2 years and a...
Replacement time for TV sets are normally distributed with a
mean of 7.2 years and a standard deviation of 1.1 years.
A) Find the probability that a randomly selected TV will have a
replacement time less than 5.0 years.
B) If you want to provide a warranty so that only 1% of the TV
sets will be replaced before the warranty expires, what is the
length of the warranty?
I am unfamiliar with using a Stand Normal Distribution chart, if...
A. A company produces steel rods. The lengths of the steel rods are normally distributed with...
A. A company produces steel rods. The lengths of the steel rods
are normally distributed with a mean of 162.4-cm and a standard
deviation of 0.6-cm. For shipment, 16 steel rods are bundled
together.
Find the probability that the average length of a randomly selected
bundle of steel rods is less than 162.6-cm.
P(¯xx¯ < 162.6-cm) =
B. A company produces steel rods. The lengths of the steel rods
are normally distributed with a mean of 246.8-cm and a standard...
A company produces steel rods. The lengths of the steel rods are normally distributed with a...
A company produces steel rods. The lengths of the steel rods are
normally distributed with a mean of 167.1-cm and a standard
deviation of 0.6-cm. For shipment, 6 steel rods are bundled
together. Round all answers to four decimal places if
necessary.
What is the distribution of XX? XX ~ N( , )
What is the distribution of ¯xx¯? ¯xx¯ ~ N( , )
For a single randomly selected steel rod, find the probability
that the length is between 166.9-cm...
A company produces steel rods. The lengths of the steel rods are normally distributed with a...
A company produces steel rods. The lengths of the steel rods are
normally distributed with a mean of 195.2-cm and a standard
deviation of 0.8-cm. For shipment, 22 steel rods are bundled
together.
Find the probability that the average length of a randomly selected
bundle of steel rods is less than 195.1-cm.
P(M < 195.1-cm) =
Enter your answer as a number accurate to 4 decimal places. Answers
obtained using exact z-scores or z-scores rounded
to 3 decimal places are...
A company produces steel rods. The lengths of the steel rods are normally distributed with a...
A company produces steel rods. The lengths of the steel rods are
normally distributed with a mean of 143.6-cm and a standard
deviation of 0.8-cm. For shipment, 41 steel rods are bundled
together. Round all answers to four decimal places if
necessary.
What is the distribution of X
? X
~ N(,)
What is the distribution of ¯x
? ¯x
~ N(,)
For a single randomly selected steel rod, find the probability
that the length is between 143.4-cm and 143.5-cm....
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