Question

In: Statistics and Probability

Replacement time for TV sets are normally distributed with a mean of 7.2 years and a...

Replacement time for TV sets are normally distributed with a mean of 7.2 years and a standard deviation of 1.1 years.

A) Find the probability that a randomly selected TV will have a replacement time less than 5.0 years.

B) If you want to provide a warranty so that only 1% of the TV sets will be replaced before the warranty expires, what is the length of the warranty?

I am unfamiliar with using a Stand Normal Distribution chart, if you could please explain how you are locating the numbers on the chart.

Solutions

Expert Solution

Hence the 1 % cut off for warranty replacement is 4.64 years.

I have bolded the required z values and corresponding probabilities for understanding.

for first question we have to find p value for z=2.00. Go through vertical z column till z=2 and horizontal z column till 00, the insecting p value of both columns will be our required p value.

In second question we have to find z value for p=0.01. Go through p-values in table and find 0.01. we find it between -2.32and -2.33 hence roughly taken z= - 2.325

z 0 -0.01 -0.02 -0.03 -0.04 -0.05 -0.06 -0.07 -0.08 -0.09
-4 0.00003 0.00003 0.00003 0.00003 0.00003 0.00003 0.00002 0.00002 0.00002 0.00002
-3.9 0.00005 0.00005 0.00004 0.00004 0.00004 0.00004 0.00004 0.00004 0.00003 0.00003
-3.8 0.00007 0.00007 0.00007 0.00006 0.00006 0.00006 0.00006 0.00005 0.00005 0.00005
-3.7 0.00011 0.0001 0.0001 0.0001 0.00009 0.00009 0.00008 0.00008 0.00008 0.00008
-3.6 0.00016 0.00015 0.00015 0.00014 0.00014 0.00013 0.00013 0.00012 0.00012 0.00011
-3.5 0.00023 0.00022 0.00022 0.00021 0.0002 0.00019 0.00019 0.00018 0.00017 0.00017
-3.4 0.00034 0.00032 0.00031 0.0003 0.00029 0.00028 0.00027 0.00026 0.00025 0.00024
-3.3 0.00048 0.00047 0.00045 0.00043 0.00042 0.0004 0.00039 0.00038 0.00036 0.00035
-3.2 0.00069 0.00066 0.00064 0.00062 0.0006 0.00058 0.00056 0.00054 0.00052 0.0005
-3.1 0.00097 0.00094 0.0009 0.00087 0.00084 0.00082 0.00079 0.00076 0.00074 0.00071
-3 0.00135 0.00131 0.00126 0.00122 0.00118 0.00114 0.00111 0.00107 0.00104 0.001
-2.9 0.00187 0.00181 0.00175 0.00169 0.00164 0.00159 0.00154 0.00149 0.00144 0.00139
-2.8 0.00256 0.00248 0.0024 0.00233 0.00226 0.00219 0.00212 0.00205 0.00199 0.00193
-2.7 0.00347 0.00336 0.00326 0.00317 0.00307 0.00298 0.00289 0.0028 0.00272 0.00264
-2.6 0.00466 0.00453 0.0044 0.00427 0.00415 0.00402 0.00391 0.00379 0.00368 0.00357
-2.5 0.00621 0.00604 0.00587 0.0057 0.00554 0.00539 0.00523 0.00508 0.00494 0.0048
-2.4 0.0082 0.00798 0.00776 0.00755 0.00734 0.00714 0.00695 0.00676 0.00657 0.00639
-2.3 0.01072 0.01044 0.01017 0.0099 0.00964 0.00939 0.00914 0.00889 0.00866 0.00842
-2.2 0.0139 0.01355 0.01321 0.01287 0.01255 0.01222 0.01191 0.0116 0.0113 0.01101
-2.1 0.01786 0.01743 0.017 0.01659 0.01618 0.01578 0.01539 0.015 0.01463 0.01426
-2 0.02275 0.02222 0.02169 0.02118 0.02068 0.02018 0.0197 0.01923 0.01876 0.01831
-1.9 0.02872 0.02807 0.02743 0.0268 0.02619 0.02559 0.025 0.02442 0.02385 0.0233
-1.8 0.03593 0.03515 0.03438 0.03362 0.03288 0.03216 0.03144 0.03074 0.03005 0.02938
-1.7 0.04457 0.04363 0.04272 0.04182 0.04093 0.04006 0.0392 0.03836 0.03754 0.03673
-1.6 0.0548 0.0537 0.05262 0.05155 0.0505 0.04947 0.04846 0.04746 0.04648 0.04551
-1.5 0.06681 0.06552 0.06426 0.06301 0.06178 0.06057 0.05938 0.05821 0.05705 0.05592
-1.4 0.08076 0.07927 0.0778 0.07636 0.07493 0.07353 0.07215 0.07078 0.06944 0.06811
-1.3 0.0968 0.0951 0.09342 0.09176 0.09012 0.08851 0.08692 0.08534 0.08379 0.08226
-1.2 0.11507 0.11314 0.11123 0.10935 0.10749 0.10565 0.10383 0.10204 0.10027 0.09853
-1.1 0.13567 0.1335 0.13136 0.12924 0.12714 0.12507 0.12302 0.121 0.119 0.11702
-1 0.15866 0.15625 0.15386 0.15151 0.14917 0.14686 0.14457 0.14231 0.14007 0.13786
-0.9 0.18406 0.18141 0.17879 0.17619 0.17361 0.17106 0.16853 0.16602 0.16354 0.16109
-0.8 0.21186 0.20897 0.20611 0.20327 0.20045 0.19766 0.19489 0.19215 0.18943 0.18673
-0.7 0.24196 0.23885 0.23576 0.2327 0.22965 0.22663 0.22363 0.22065 0.2177 0.21476
-0.6 0.27425 0.27093 0.26763 0.26435 0.26109 0.25785 0.25463 0.25143 0.24825 0.2451
-0.5 0.30854 0.30503 0.30153 0.29806 0.2946 0.29116 0.28774 0.28434 0.28096 0.2776
-0.4 0.34458 0.3409 0.33724 0.3336 0.32997 0.32636 0.32276 0.31918 0.31561 0.31207
-0.3 0.38209 0.37828 0.37448 0.3707 0.36693 0.36317 0.35942 0.35569 0.35197 0.34827
-0.2 0.42074 0.41683 0.41294 0.40905 0.40517 0.40129 0.39743 0.39358 0.38974 0.38591
-0.1 0.46017 0.4562 0.45224 0.44828 0.44433 0.44038 0.43644 0.43251 0.42858 0.42465
0 0.5 0.49601 0.49202 0.48803 0.48405 0.48006 0.47608 0.4721 0.46812 0.46414
z 0 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09
0 0.5 0.50399 0.50798 0.51197 0.51595 0.51994 0.52392 0.5279 0.53188 0.53586
0.1 0.53983 0.5438 0.54776 0.55172 0.55567 0.55962 0.5636 0.56749 0.57142 0.57535
0.2 0.57926 0.58317 0.58706 0.59095 0.59483 0.59871 0.60257 0.60642 0.61026 0.61409
0.3 0.61791 0.62172 0.62552 0.6293 0.63307 0.63683 0.64058 0.64431 0.64803 0.65173
0.4 0.65542 0.6591 0.66276 0.6664 0.67003 0.67364 0.67724 0.68082 0.68439 0.68793
0.5 0.69146 0.69497 0.69847 0.70194 0.7054 0.70884 0.71226 0.71566 0.71904 0.7224
0.6 0.72575 0.72907 0.73237 0.73565 0.73891 0.74215 0.74537 0.74857 0.75175 0.7549
0.7 0.75804 0.76115 0.76424 0.7673 0.77035 0.77337 0.77637 0.77935 0.7823 0.78524
0.8 0.78814 0.79103 0.79389 0.79673 0.79955 0.80234 0.80511 0.80785 0.81057 0.81327
0.9 0.81594 0.81859 0.82121 0.82381 0.82639 0.82894 0.83147 0.83398 0.83646 0.83891
1 0.84134 0.84375 0.84614 0.84849 0.85083 0.85314 0.85543 0.85769 0.85993 0.86214
1.1 0.86433 0.8665 0.86864 0.87076 0.87286 0.87493 0.87698 0.879 0.881 0.88298
1.2 0.88493 0.88686 0.88877 0.89065 0.89251 0.89435 0.89617 0.89796 0.89973 0.90147
1.3 0.9032 0.9049 0.90658 0.90824 0.90988 0.91149 0.91308 0.91466 0.91621 0.91774
1.4 0.91924 0.92073 0.9222 0.92364 0.92507 0.92647 0.92785 0.92922 0.93056 0.93189
1.5 0.93319 0.93448 0.93574 0.93699 0.93822 0.93943 0.94062 0.94179 0.94295 0.94408
1.6 0.9452 0.9463 0.94738 0.94845 0.9495 0.95053 0.95154 0.95254 0.95352 0.95449
1.7 0.95543 0.95637 0.95728 0.95818 0.95907 0.95994 0.9608 0.96164 0.96246 0.96327
1.8 0.96407 0.96485 0.96562 0.96638 0.96712 0.96784 0.96856 0.96926 0.96995 0.97062
1.9 0.97128 0.97193 0.97257 0.9732 0.97381 0.97441 0.975 0.97558 0.97615 0.9767
2 0.97725 0.97778 0.97831 0.97882 0.97932 0.97982 0.9803 0.98077 0.98124 0.98169
2.1 0.98214 0.98257 0.983 0.98341 0.98382 0.98422 0.98461 0.985 0.98537 0.98574
2.2 0.9861 0.98645 0.98679 0.98713 0.98745 0.98778 0.98809 0.9884 0.9887 0.98899
2.3 0.98928 0.98956 0.98983 0.9901 0.99036 0.99061 0.99086 0.99111 0.99134 0.99158
2.4 0.9918 0.99202 0.99224 0.99245 0.99266 0.99286 0.99305 0.99324 0.99343 0.99361
2.5 0.99379 0.99396 0.99413 0.9943 0.99446 0.99461 0.99477 0.99492 0.99506 0.9952
2.6 0.99534 0.99547 0.9956 0.99573 0.99585 0.99598 0.99609 0.99621 0.99632 0.99643
2.7 0.99653 0.99664 0.99674 0.99683 0.99693 0.99702 0.99711 0.9972 0.99728 0.99736
2.8 0.99744 0.99752 0.9976 0.99767 0.99774 0.99781 0.99788 0.99795 0.99801 0.99807
2.9 0.99813 0.99819 0.99825 0.99831 0.99836 0.99841 0.99846 0.99851 0.99856 0.99861
3 0.99865 0.99869 0.99874 0.99878 0.99882 0.99886 0.99889 0.99893 0.99896 0.999
3.1 0.99903 0.99906 0.9991 0.99913 0.99916 0.99918 0.99921 0.99924 0.99926 0.99929
3.2 0.99931 0.99934 0.99936 0.99938 0.9994 0.99942 0.99944 0.99946 0.99948 0.9995
3.3 0.99952 0.99953 0.99955 0.99957 0.99958 0.9996 0.99961 0.99962 0.99964 0.99965
3.4 0.99966 0.99968 0.99969 0.9997 0.99971 0.99972 0.99973 0.99974 0.99975 0.99976
3.5 0.99977 0.99978 0.99978 0.99979 0.9998 0.99981 0.99981 0.99982 0.99983 0.99983
3.6 0.99984 0.99985 0.99985 0.99986 0.99986 0.99987 0.99987 0.99988 0.99988 0.99989
3.7 0.99989 0.9999 0.9999 0.9999 0.99991 0.99991 0.99992 0.99992 0.99992 0.99992
3.8 0.99993 0.99993 0.99993 0.99994 0.99994 0.99994 0.99994 0.99995 0.99995 0.99995
3.9 0.99995 0.99995 0.99996 0.99996 0.99996 0.99996 0.99996 0.99996 0.99997 0.99997
4 0.99997 0.99997 0.99997 0.99997 0.99997 0.99997 0.99998 0.99998 0.99998 0.99998

Related Solutions

Replacement times for TV sets are normally distributed with a mean of 8.2 years and a...
Replacement times for TV sets are normally distributed with a mean of 8.2 years and a standard deviation of 1.1 years. (Change the final answer to a % and keep 2 decimal places) a) Find the probability that a randomly selected TV set will have a replacement time between 9.5 and 10.5 years. (Include diagram) b) Find the probability that 35 randomly selected TV sets will have a mean replacement time less than 8.0 years. (Include diagram)
4. Replacement times for TV sets are normally distributed with a mean of 8.2 years and...
4. Replacement times for TV sets are normally distributed with a mean of 8.2 years and a standard deviation of 1.1 years. (Change the final answer to a % and keep 2 decimal places) a) Find the probability that a randomly selected TV set will have a replacement time between 9.5 and 10.5 years. (Include diagram) b) Find the probability that 35 randomly selected TV sets will have a mean replacement time less than 8.0 years. (Include diagram)
Replacement times for Timex watches are normally distributed with a mean of 10.2 years and a...
Replacement times for Timex watches are normally distributed with a mean of 10.2 years and a standard deviation of 3.1 years (Based on data from “Getting Things Fixed”, Consumer Reports). a. What percentage of watches should last between 8 and 9 years? b. At least how many years should the longest 25% of all watches last? c. If Timex wants to provide a warranty so that only 1% of the watches will be replaced before the warranty expires, what is...
TV sets: According to the Nielsen Company, the mean number of TV sets in a U.S....
TV sets: According to the Nielsen Company, the mean number of TV sets in a U.S. household in 2013 was 2.24. Assume the standard deviation is 1.2. A sample of 80 households is drawn. Use the Cumulative Normal Distribution Table if needed. Part 1 of 5 What is the probability that the sample mean number of TV sets is greater than 2? Round your answer to four decimal places. The probability that the sample mean number of TV sets is...
TV sets: According to the Nielsen Company, the mean number of TV sets in a U.S....
TV sets: According to the Nielsen Company, the mean number of TV sets in a U.S. household in a recent year was 2.24. Assume the standard deviation is 1.2. A sample of 85 households is drawn. What is the probability that the sample mean number of TV sets is between 2.5 and 3? Find the 30th percentile of the sample mean.
TV sets: According to the Nielsen Company, the mean number of TV sets in a U.S....
TV sets: According to the Nielsen Company, the mean number of TV sets in a U.S. household in 2013 was 2.24. Assume the standard deviation is 1.4. A sample of 80 households is drawn. Use the Cumulative Normal Distribution Table if needed. Part 1 of 5 What is the probability that the sample mean number of TV sets is greater than 2? Round your answer to four decimal places. The probability that the sample mean number of TV sets is...
TV sets: According to the Nielsen Company, the mean number of TV sets in a U.S....
TV sets: According to the Nielsen Company, the mean number of TV sets in a U.S. household in 2013 was 2.24 . Assume the standard deviation is 1.2 . A sample of 95 households is drawn. Use the Cumulative Normal Distribution Table if needed. What is the probability that the sample mean number of TV sets is greater than 2? Round your answer to four decimal places. What is the probability that the sample mean number of TV sets is...
A sample consists of 75 TV sets purchased several years ago. The replacement times of those...
A sample consists of 75 TV sets purchased several years ago. The replacement times of those TV sets have a mean of 8.2 years. Assume σ= 1.1 years. Find the 95% confidence interval. Why are you finding a confidence interval for Question 1? A random sample of 61 Foreign Language movies made in the last 10 years has a mean length of 135.7 minutes with a standard deviation of 13.7 minutes. Construct a 95% confidence interval. For items 1 and...
Suppose that replacement times for washing machines are normally distributed with a mean of 9.3 and...
Suppose that replacement times for washing machines are normally distributed with a mean of 9.3 and a standard deviation of 1.1 years. Find the probability that 70 randomly selected washing machines will have a mean replacement time less than 9.1 years.
Last year the commercial time for a broadcast on a particular TV channel was normally distributed...
Last year the commercial time for a broadcast on a particular TV channel was normally distributed with Expectation 6.1 minutes. The channel manager claims that this year there has been a change in the life expectancy of the broadcast time. To test his claim, he modeled 16 hours of transmission and found that the average commercial time per hour of transmission Is 5.7 hours with a standard deviation of 1.2 hours. A. Would you justify the channel manager's claim with...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT