In: Statistics and Probability
onduct the hypothesis test and provide the test statistic and the critical value, and state the conclusion.
A person drilled a hole in a die and filled it with a lead
weight, then proceeded to roll it 200 times. Here are the observed
frequencies for the outcomes of 1, 2, 3, 4, 5, and 6, respectively:
28, 27, 40, 38, 26, 41. Use a 0.01 significance level to test the
claim that the outcomes are not equally likely. Does it appear that
the loaded die behaves differently than a fair die?
The test statistic is __________.
(Round to three decimal places as needed.)
The critical value is __________ .
(Round to three decimal places as needed.)
Given data :
n=200
k=6=Number of categories
Hypothesis:
at least one Pi is not equal to 1/6
Test statistics:
Where Oi=Obsered frequecy
Ei=Expected Frequency
k=Number of categories
Oi | Ei | Oi-Ei | (Oi-Ei)2 | (Oi-Ei)2/ Ei | |
1 | 28 | 33.3333 | -5.3333 | 28.4444 | 0.8533 |
2 | 27 | 33.3333 | -6.3333 | 40.1111 | 1.2033 |
3 | 40 | 33.3333 | 6.6666 | 44.4444 | 1.3333 |
4 | 38 | 33.3333 | 4.6666 | 21.7778 | 0.6533 |
5 | 26 | 33.3333 | -7.3333 | 53.7778 | 1.6133 |
6 | 41 | 33.3333 | 7.6667 | 58.7778 | 1.7633 |
7.420 |
Degrees of freedom=k-1=5
Critical Value:
Critical value :is the value appering in the table for the
specifies statistical test with what computed null hypothesis can
be rejected
Chi-square critical value with significance level 0.01 with d.f =5 is given by
=15.086
Decision
Test statistics=7.420 < Critical valuw 15.086
We failed to reject H0
There is not enough evidence to reject the null hypothesis and we have not sufficient eidence to conclude that the loaded die behave differently than a fair die