Question

In: Statistics and Probability

In 1998 a national vital statistics report indicated that about 2.3 % of all births produced...

In 1998 a national vital statistics report indicated that about 2.3 % of all births produced twins. Is the rate of twin births the same among very young​ mothers? Data from a large city hospital found only 9 sets of twins were born to 481 teenage girls. Test an appropriate hypothesis and state your conclusion. Be sure the appropriate assumptions and conditions are satisfied before you proceed.

Are the assumptions and the conditions to perform a​ one-proportion z-test​ met?

No Yes

State the null and alternative hypotheses. Choose the correct answer below.

A. H0​: pequals0.023 HA​: pnot equals0.023

B. H0​: pequals0.023 HA​: pless than0.023

C. H0​: pequals0.023 HA​: pgreater than0.023

D. The assumptions and conditions are not​ met, so the test cannot proceed.

Determine the​ z-test statistic. Select the correct choice below​ and, if​ necessary, fill in the answer box to complete your choice.

A. z= __________ ​(Round to two decimal places as​ needed.)

B. The assumptions and conditions are not​ met, so the test cannot proceed.

Find the​ P-value. Select the correct choice below​ and, if​ necessary, fill in the answer box to complete your choice.

A. ​P-value+ ______ ​(Round to three decimal places as​ needed.)

B. The assumptions and conditions are not​ met, so the test cannot proceed.

What is your​ conclusion? Choose the correct answer below.

A) Reject H0. The proportion of twin births for teenage mothers is different from the proportion of twin births for all mothers.

B) Fail to reject H0. The proportion of twin births for teenage mothers is not different from the proportion of twin births for all mothers.

C)Reject H0. The proportion of twins births for teenage mothers is greater than the proportion of twin births for all mothers.

D) The assumptions and conditions are not met, so the test cannot proceed.

Solutions

Expert Solution

Observed Hypothesized
0.0187 0.023 p (as decimal)
9/481 11/481 p (as fraction)
9. 11.063 X
481 481 n
0.0068 std. error
-0.63 z
.5303 p-value (two-tailed)
0.0066 confidence interval 95.% lower
0.0308 confidence interval 95.% upper
0.0121 margin of error

Are the assumptions and the conditions to perform a​ one-proportion z-test​ met?

Yes

State the null and alternative hypotheses. Choose the correct answer below.

A. H0​: pequals0.023 HA​: pnot equals0.023

Determine the​ z-test statistic. Select the correct choice below​ and, if​ necessary, fill in the answer box to complete your choice.

A. z= -0.63​(Round to two decimal places as​ needed.)

B. The assumptions and conditions are not​ met, so the test cannot proceed.

Find the​ P-value. Select the correct choice below​ and, if​ necessary, fill in the answer box to complete your choice.

A. ​P-value= 0.5303​(Round to three decimal places as​ needed.)

What is your​ conclusion? Choose the correct answer below.

B) Fail to reject H0. The proportion of twin births for teenage mothers is not different from the proportion of twin births for all mothers.


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