In: Statistics and Probability
In this project you will be asked to find confidence interval and perform a hypothesis test for the mean of one population.
Be sure to show all your work neatly.
Instructions
The table provided below contains pulse rates after running for 1 minute, collected from females who drink alcohol ("Pulse rates before," 2013). The mean pulse rate after running for 1 minute of females who do not drink is 97 beats per minute. Do the data show that the mean pulse rate of females who do drink alcohol is higher than the mean pulse rate of females who do not drink? Test at the 5% level.
Pulse Rates of Woman Who Use Alcohol
176 |
150 |
150 |
115 |
129 |
160 |
120 |
125 |
89 |
132 |
120 |
120 |
68 |
87 |
88 |
72 |
77 |
84 |
92 |
80 |
60 |
67 |
59 |
64 |
88 |
74 |
68 |
Hypothesised population mean, =97
Sample size, n =27
Degrees of freedom, df =n - 1 =27 - 1 =26
Sample mean, = =100.52
Sample std.deviation, s = =33.5609
Standard Error, SE =s/ =33.5609/ =6.46
a.
The appropriate test is one sample t-test because the sample size, n < 30 and also the population standard deviation, is unknown.
b.
Assumptions:
1) The dependent variable must be continuous, i.e., interval or ratio.
2) The observations are independent of one another.
3) The dependent variable should be normally or approximately normally distributed.
4) The dependent variable should not have any outliers.
c.
Null Hypothesis, H0:
The mean pulse rate of females who do drink alcohol is not significantly higher than the mean pulse rate of females who do not drink. 97
d.
Alternative Hypothesis, H1:
The mean pulse rate of females who do drink alcohol is significantly higher than the mean pulse rate of females who do not drink. > 97
e.
This is a right-tailed test because we want to determine if the population mean pulse rate of females who do drink alcohol is higher than the hypothesised population mean of 97.
f.
Significance level, =5% =0.05
g.
Test statistic, t =()/SE =(100.52 - 97)/6.46 =0.5449
h.
For a right-tailed test, at df =26, the p-value for the test statistic, t =0.5449 is: p-value =0.2952
i.
We do not reject the null hypothesis because p-value of 0.2952 > 0.05 significance level.
j.
Conclusion:
We do not have sufficient statistical evidence to claim that the mean pulse rate of females who do drink alcohol is higher than the mean pulse rate of females who do not drink.
k.
At 95% confidence level, for a two-tailed case, t-critical =2.06
Margin of Error, MoE =t-critical*SE =2.06*6.46 =13.31
Two-sided 95% confidence interval for the population mean, =MoE =100.5213.31 =[87.21, 113.83].
l.
Interpretation:
We are 95% confident that the interval [87.21, 113.83] contains the true population mean pulse rate, of females who do drink alcohol.