Question

In: Statistics and Probability

The following data show the brand, price ($), and the overall score for 6 stereo headphones...

The following data show the brand, price ($), and the overall score for 6 stereo headphones that were tested by Consumer Reports. The overall score is based on sound quality and effectiveness of ambient noise reduction. Scores range from 0 (lowest) to 100 (highest). The estimated regression equation for these data is  = 23.395 + 0.316 x, where x = price ($) and y = overall score.

Brand Price ($) Score
Bose 180 75
Scullcandy 150 72
Koss 95 61
Phillips/O'Neill 70 56
Denon 70 40
JVC 35 26

Round your answers to three decimal places.

a. Compute SST, SSR, and SSE.

SST
SSR
SSE

b. Compute the coefficient of determination r 2. Comment on the goodness of fit.

r 2 =

SelectThe least squares line provided a very good fitThe least squares line provided a bad fitItem 5

c. What is the value of the sample correlation coefficient?

r =

Solutions

Expert Solution

Line of Regression Y on X i.e Y = bo + b1 X
X Y (Xi - Mean)^2 (Yi - Mean)^2 (Xi-Mean)*(Yi-Mean)
180 75 6400 400 1600
150 72 2500 289 850
95 61 25 36 -30
70 56 900 1 -30
70 40 900 225 450
35 26 4225 841 1885

calculation procedure for regression
mean of X = ∑ X / n = 100
mean of Y = ∑ Y / n = 55
∑ (Xi - Mean)^2 = 14950
∑ (Yi - Mean)^2 = 1792
∑ (Xi-Mean)*(Yi-Mean) = 4725
b1 = ∑ (Xi-Mean)*(Yi-Mean) / ∑ (Xi - Mean)^2
= 4725 / 14950
= 0.316
bo = ∑ Y / n - b1 * ∑ X / n
bo = 55 - 0.316*100 = 23.395
value of regression equation is, Y = bo + b1 X
Y'=23.395+0.316* X          

a.

( X) ( Y) X^2 Y^2 X*Y
180 75 32400 5625 13500
150 72 22500 5184 10800
95 61 9025 3721 5795
70 56 4900 3136 3920
70 40 4900 1600 2800
35 26 1225 676 910

calculation procedure for correlation
sum of (x) = ∑x = 600
sum of (y) = ∑y = 330
sum of (x^2)= ∑x^2 = 74950
sum of (y^2)= ∑y^2 = 19942
sum of (x*y)= ∑x*y = 37725
to caluclate value of r( x,y) = covariance ( x,y ) / sd (x) * sd (y)
covariance ( x,y ) = [ ∑x*y - N *(∑x/N) * (∑y/N) ]/n-1
= 37725 - [ 6 * (600/6) * (330/6) ]/6- 1
= 787.5
and now to calculate r( x,y) = 787.5/ (SQRT(1/6*37725-(1/6*600)^2) ) * ( SQRT(1/6*37725-(1/6*330)^2)
=787.5 / (49.917*17.282)
=0.913
value of correlation is =0.913
b.

coeffcient of determination = r^2 = 0.833
properties of correlation
1. If r = 1 Corrlation is called Perfect Positive Correlation
2. If r = -1 Correlation is called Perfect Negative Correlation
3. If r = 0 Correlation is called Zero Correlation
& with above we conclude that correlation ( r ) is = 0.9129> 0 ,perfect positive correlation              
c.

value of correlation is =0.913


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