Nitrous acid has a Ka of 4.0 * 10-4. in 1.00 L of solution, 0.670 moles...

Nitrous acid has a Ka of 4.0 * 10-4. in 1.00 L of solution, 0.670 moles of nitrous acid (HNO2) are added to 0.281 moles of NaOH. What is the final pH?

Expert Solution

HNO2 + NaOH ---------> NaNO2 + H2O

I 0.67 0.281 0

C -0.281 -0.281 0.281

E 0.389 0 0.281

Pka = -logKa

= -log4*10^-4

= 3.3979

PH = Pka + log[NaNO2]/[HNO2]

= 3.3979 + log0.281/0.389

= 3.3979-0.1412 = 3.2567

queen_honey_blossom answered 1 year ago

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