Question

In: Statistics and Probability

In a survey of 1007 adults aged 18 to 74 living in a city, the prevalence...

In a survey of 1007 adults aged 18 to 74 living in a city, the prevalence of smokers was found to be 368.
Build a 90% confidence interval for the proportion of smokers.
Interpret the interval above.
Build a 95% confidence interval for the proportion of smokers.
Interpret the interval above. Compare with 90% CI.

Solutions

Expert Solution

We are 90% confident that the proportion of smokers lies between the 0.34 to 0.39.

We are 95% confident that the proportion of smokers lies between the 0.336 and 0.395 and the 95 % Confidence interval is wider than the 90% confidence interval.

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