In: Statistics and Probability
A random sample of 400 students shows the following means of transportation to campus:
drive own auto public transportation other
men 150 40 10
women 115 65 30
Using SPSS, test whether the method of transportation is independent of method of sex. (α = .05)
A random sample of 400 students shows the following means of transportation to campus:
drive own auto public transportation other
men 150 40 10
women 115 65 30
Using SPSS, test whether the method of transportation is independent of method of sex. (α = .05)
Enter data in three columns, sex, transport and wt.
| 
 sex  | 
 transport  | 
 wt  | 
| 
 1  | 
 1  | 
 150  | 
| 
 1  | 
 2  | 
 40  | 
| 
 1  | 
 3  | 
 10  | 
| 
 2  | 
 1  | 
 115  | 
| 
 2  | 
 2  | 
 65  | 
| 
 2  | 
 3  | 
 30  | 
Now Data---- weight cases -----weight cases by wt.
Now
Use Analyze----Descriptive statistics ------Crosstabs
Select sex in Rows and transport is columns
In the statistics submenu select chi square and continue and ok
| 
 sex * transport Crosstabulation  | 
|||||
| 
 Count  | 
|||||
| 
 transport  | 
 Total  | 
||||
| 
 drive own auto  | 
 public transportation  | 
 other  | 
|||
| 
 sex  | 
 men  | 
 150  | 
 40  | 
 10  | 
 200  | 
| 
 women  | 
 115  | 
 65  | 
 30  | 
 210  | 
|
| 
 Total  | 
 265  | 
 105  | 
 40  | 
 410  | 
|
| 
 Chi-Square Tests  | 
|||
| 
 Value  | 
 df  | 
 Asymptotic Significance (2-sided)  | 
|
| 
 Pearson Chi-Square  | 
 20.343a  | 
 2  | 
 .000  | 
| 
 Likelihood Ratio  | 
 20.867  | 
 2  | 
 .000  | 
| 
 Linear-by-Linear Association  | 
 20.119  | 
 1  | 
 .000  | 
| 
 N of Valid Cases  | 
 410  | 
||
| 
 a. 0 cells (0.0%) have expected count less than 5. The minimum expected count is 19.51.  | 
|||
Calculated chi square = 20.343, P=0.000 which is < 0.05 level of significance. Ho is rejected. We conclude that method of transportation is not independent of method of sex.