Question

Please write a complete C coding program (NOT C++) that has the following: (including comments)

- declares two local integers x and y

- defines a global structure containing two pointers (xptr, yptr) and an integer (z)
- declares a variable (mst) by the type of previous structure
- requests the values of x and y from the user using only one scanf statement
- sets the first pointer in the struct to point to x
- sets the second pointer in the struct to point to y
- uses the structure to print out the values in x and y (do not print x and y values directly)

- Declare a variable (mstptr) that is a pointer to the structure and make it point to the structure you already declared (mst)

- Using the pointer to the structure set the integer z in the structure to the number 5.

- Using the pointer to the structure display the value of the integer and the values pointed to by the two pointers (must use -> operator)

Answer 1

#include<stdio.h>

struct Point // declare and define a structure named Point with elements as *xptr, *yptr and z

{
   int *xptr;
   int *yptr;
   int z;
};

int main()
{

   int x,y; // declare variables x and y

   struct Point mst; // declare structure element mst

   printf("Enter value of x and y : ");
   scanf("%d%d",&x,&y); // read x and y values
   mst.xptr = &x; // assign the first pointer in the struct to point to x
   mst.yptr = &y; // assign the second pointer in the struct to point to y

   printf("Printing the value using mst pointer\n"); // display x and y values using the pointer mst    
   printf(" x = %d\n",*mst.xptr);
   printf(" y = %d\n",*mst.yptr);
struct Point *mstptr=&mst; //Declare a variable mstptr that is a pointer to the structure

   mstptr->z=5;    //assign value 5 to z
   printf("\nPrinting the value using structure pointer\n");
   //display the values of x and y and z using structure point
   printf(" x = %d\n",*mstptr->xptr);
   printf(" y = %d\n",*mstptr->yptr);
   printf(" z = %d\n",mstptr->z);
   return 0;

}