In: Statistics and Probability
Solution:
Given: Take two cards from a deck without replacement.
Find:
P( getting a red queen and then another red card) =.............?
P( Red Queen and Another any Red card) =.................?
P( Red Queen and Another any Red card) = P( Red Queen) X P( Another any Red card)
We have 4 cards of Queen out of which two are Red
and there are total 26 red cards in 52 playing cards.
thus a red queen card can be selected in 2 ways
and for second draw, we have 26-1 = 25 red cards
thus
P( Red Queen and Another any Red card) = P( Red Queen) X P( Another any Red card)
P( Red Queen and Another any Red card) = ( 2 /52 ) X ( 25 / 51)
Here number is reduced by 1 , since we are not replacing card.
P( Red Queen and Another any Red card) = 0.0384615 X 0.4901961
P( Red Queen and Another any Red card) = 0.0188537
P( Red Queen and Another any Red card) = 0.018854
(Round final answer to specified number of decimal places)