A 515-Hz tuning fork is struck and placed next to a tube with a movable piston,...

A 515-Hz tuning fork is struck and placed next to a tube with a movable piston, creating a tube with a variable length. The piston is slid down the pipe and resonance is reached when the piston is 112.5 cm from the open end. The next resonance is reached when the piston is 82.5 cm from the open end. Round all answers to one decimal place.

Hint (a)

What is the speed of sound in the tube?
v=v= m/s
How far from the open end will the piston cause the next mode of resonance?
L=L= cm

Expert Solution

genius_generous answered 2 years ago

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