A 515-Hz tuning fork is struck and placed next to a tube with a movable piston,...

A 515-Hz tuning fork is struck and placed next to a tube with a movable piston, creating a tube with a variable length. The piston is slid down the pipe and resonance is reached when the piston is 112.5 cm from the open end. The next resonance is reached when the piston is 82.5 cm from the open end. Round all answers to one decimal place.

Hint (a)

What is the speed of sound in the tube?
v=v= m/s
How far from the open end will the piston cause the next mode of resonance?
L=L= cm

Expert Solution

genius_generous answered 1 year ago

A tuning fork on a movable cart is vibrating at a frequency of 1500 Hz. As...

A tuning fork on a movable cart is vibrating at a frequency of 1500 Hz. As you are walking past the cart at 2 m/sec, the cart begins accelerating uniformly in the direction you’re walking. When it is 20 m in front of you, the sound of the tuning fork is heard to be at a frequency of 1380 Hz. Knowing that the air temperature at your location is 23.6°C, determine the acceleration of the cart.

A tuning fork is placed against the forehead of a patient. The sound is loudest in...

A tuning fork is placed against the forehead of a patient. The sound is loudest in the left ear. What can you determine about the patient’s hearing? What is happening in the left ear and the right ear? Begin your Internet search with the National Institute of Deafness and Other Communication Disorders website. Also, search for deafness, hearing, and cochlea. Be detailed in your explanation and support your answer with facts from your textbook, research, and articles from scholarly journals....

a) With a 660 Hz tuning fork, you measure a distance of 25 +/- 2 cm...

a) With a 660 Hz tuning fork, you measure a distance of 25 +/- 2 cm between adjacent nodes. Is the value of c=340 m/s within the uncertainty of your measured value? b) If you blow air along the top of an open soda bottle you can excite a standing wave in the bottle and you hear a sound. Explain what happens if you put osme water into the bottle and then perform the same experiment! Please show calculations and/or...

A tuning fork generates sound waves with a frequency of 230 Hz. The waves travel in...

A tuning fork generates sound waves with a frequency of 230 Hz. The waves travel in opposite directions along a hallway, are reflected by walls, and return. The hallway is46.0 m long and the tuning fork is located 14.0 m from one end. What is the phase difference between the reflected waves when they meet at the tuning fork? The speed of sound in air is 343 m/s. (Ans in degrees)

A guitarist tunes one of her strings to a 440 Hz tuning fork. Initially, a beat...

A guitarist tunes one of her strings to a 440 Hz tuning fork. Initially, a beat frequency of 5 Hz is heard when the string and tuning fork are sounded. When the guitarist tightens the string slowly and steadily, the beat frequency decreases to 4 Hz. What was the initial frequency of the string?

Vibration from a 620 Hz tuning fork sets up standing waves on a string clamped at...

Vibration from a 620 Hz tuning fork sets up standing waves on a string clamped at both ends (one of which you may take as x=0). The travelling wave speed on this string is 440 m/s. The standing wave has four anti-nodes and an amplitude of 2.0 mm. (a) What is the length of the string? ___ m (b) Write an equation for the transverse displacement of the string as a function of position and time: y(x,t) = ( ___...

Atubeisopenonlyatoneend.Acertainharmonicproducedby the tube has a frequency of 450 Hz. The next higher harmonic has a frequency...

Atubeisopenonlyatoneend.Acertainharmonicproducedby the tube has a frequency of 450 Hz. The next higher harmonic has a frequency of 750 Hz. The speed of sound in air is 343 m /s. (a) What is the integer n that describes the harmonic whose frequency is 450 Hz? (b) What is the length of the tube?

A musician is tuning the pitch of a violin using a sound fork at 3,000 Hz. He first hears the combined sound intensity rise and fall with a time of 0.25 s between the maximum intensity and the succeeding minimum intensity.

A musician is tuning the pitch of a violin using a sound fork at 3,000 Hz. He first hears the combined sound intensity rise and fall with a time of 0.25 s between the maximum intensity and the succeeding minimum intensity. As he tightens the string, the time between the intensity maximums becomes longer. What is the pitch of the violin string at first?

Question