Imagine that a relaxed sarcomere is 2.4 μm long and that a contracted sarcomere is 2.1 μm long.

Imagine that a relaxed sarcomere is 2.4 μm long and that a contracted sarcomere is 2.1 μm long. Imagine further that the thin filaments are 1.0 μm long and the thick filaments are 1.5 μm long. To the nearest hundredths, what is the difference between the overlap (overlap of one thin filament with the thick filament) that occurs in a contracted sarcomere and the overlap that occurs in a relaxed sarcomere? It might help to draw a crude model of the sarcomere to help you visualize this problem.

Expert Solution

The difference between the length of contracted and relaxed sarcomere is 0.4m.
Overlap value for contracted sarcomere is 0.75m. 0.55m is the overlapping value in the case of relaxed sarcomere.
The difference between these overlap gives the value of 0.20m.

gladiator answered 2 years ago

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