In: Statistics and Probability
Consumer Reports tested 11 brands of vanilla yoghurt and found these numbers of calories per serving:
130 160 150 120 120 110 170 160 110 130 90
Use a 0.05 significance level to test the claim that the mean serving is equal to 120 calories, as a diet guide claim.
1. State the hypotheses and identify the claim
2. Find the critical value or values
3. Find the test statistic. First state the calculator command used to find it.
4. Make the decision about the null hypothesis
5. Draw conclusion about the claim
Solution:
x | x2 |
130 | 16900 |
160 | 25600 |
150 | 22500 |
120 | 14400 |
120 | 14400 |
110 | 12100 |
170 | 28900 |
160 | 25600 |
110 | 12100 |
130 | 16900 |
90 | 8100 |
∑x=1450 | ∑x2=197500 |
Mean ˉx=∑xn
=130+160+150+120+120+110+170+160+110+130+90/11
=1450/11
=131.8182
Sample Standard deviation S=√∑x2-(∑x)2nn-1
=√197500-(1450)211/10
=√197500-191136.3636/10
=√6363.6364/10
=√636.3636
=25.2262
This is the two tailed test .
The null and alternative hypothesis is ,
H0 : = 120
Ha : 120
Test statistic = t
= ( - ) / S / n
= (131.82-120) / 25.23 / 11
= 1.554
Test statistic = t = 1.554
P-value =0.1513
= 0.05
P-value >
0.1513 > 0.05
Fail to reject the null hypothesis .
There is insufficient evidence to suggest that