Question

In: Statistics and Probability

A consumer group tested 11 brands of vanilla yogurt and found the numbers below for calories...

A consumer group tested 11 brands of vanilla yogurt and found the numbers below for calories per serving. find the test statistic (t) and the P-value

130
160
145
115
125
110
175
155
110
125
95


Solutions

Expert Solution

in question mu0 is not given so i considered it as 120,if there is any change ,u can comment so that i will provide the solution..Thank you

orchestra answered 1 year ago
Next > < Previous

Related Solutions

Consumer Reports tested 11 brands of vanilla yogurt and found these numbers of calories per serving:...
Consumer Reports tested 11 brands of vanilla yogurt and found these numbers of calories per serving: 130, 160, 150, 120, 90, 110, 170, 140, 110, 130, 90 If we want to create a 95% confidence interval for the average calorie content of vanilla yogurt, what would be the standard error of the sample average? (Round to two decimal places.)
Consumer Reports tested 11 brands of vanilla yoghurt and found these numbers of calories per serving:...
Consumer Reports tested 11 brands of vanilla yoghurt and found these numbers of calories per serving: 130 160 150 120 120 110 170 160 110 130 90 Use a 0.05 significance level to test the claim that the mean serving is equal to 120 calories, as a diet guide claim. 1. State the hypotheses and identify the claim 2. Find the critical value or values 3. Find the test statistic. First state the calculator command used to find it.   4....
A company tested 11 random brands of vanilla yogurt and found the number of calories per...
A company tested 11 random brands of vanilla yogurt and found the number of calories per serving given below.​ (Note that more than 110 different brands of vanilla yogurt​ exist.) Complete parts a through c. 140 160 140 110 120 120 170 160 100 120 80 Is the Independence Assumption​ met? Is the Randomization Condition met or is the sample suitably​ representative? Is the​ 10% Condition​ met? Is the Nearly Normal Condition​ met? ​b) Find a​ 95% confidence interval for...
A company tested 11 random brands of vanilla yogurt and found the number of calories per...
A company tested 11 random brands of vanilla yogurt and found the number of calories per serving given below.​ (Note that more than 110 different brands of vanilla yogurt​ exist.) Complete parts a through c. 120  160  150 130    130   110    170    160    110 130    80     ​a) Check the assumptions and conditions for inference. Is the Independence Assumption​ met? Yes No Is the Randomization Condition met or is the sample suitably​ representative? Yes No Is the​ 10% Condition​ met? No...
10 brands of vanilla yogurt and found these numbers of calories per serving: 130 160 150...
10 brands of vanilla yogurt and found these numbers of calories per serving: 130 160 150 120 110 170 160 110 130 90 - Check the assumptions and conditions for inference. -Create a 95% confidence interval for the average calorie content of vanilla yogurt. -A diet guide claims that you will get an average of 120 calories from a serving of vanilla yogurt. What does the evidence above indicate? Use your confidence interval to test an appropriate hypothesis and state...
QUESTION 1 A consumer advocacy group compares the amount of nicotine in two brands of cigarettes....
QUESTION 1 A consumer advocacy group compares the amount of nicotine in two brands of cigarettes. A sample of 64 cigarettes from Brand A has an average of 1.95 mg with a standard deviation of 0.24 mg. A sample of 81 cigarettes from Brand B has an average of 1.85 mg and a standard deviation of 0.22.   Suppose you want to estimate how much more nicotine is in Brand A cigarettes in general using a 90% confidence interval. 1. The...
5. A researcher tested a group of 11 participants with regards to their short term memory...
5. A researcher tested a group of 11 participants with regards to their short term memory on a test of a random string of digits. The collected data was as follows 7, 9, 8, 10, 8, 6, 7, 8, 7, 6, 1 (M = 7, S = 2.32). Use this sample data to,  Make a point estimation.  Construct an interval estimate with a 80% confidence interval.  Construct an interval estimate with a 95% confidence interval.
A consumer products testing group is evaluating two competing brands of tires, Brand 1 and Brand...
A consumer products testing group is evaluating two competing brands of tires, Brand 1 and Brand 2. Tread wear can vary considerably depending on the type of car, and the group is trying to eliminate this effect by installing the two brands on the same random sample of 10 cars. In particular, each car has one tire of each brand on its front wheels, with half of the cars chosen at random to have Brand 1 on the left front...
A consumer products testing group is evaluating two competing brands of tires, Brand 1 and Brand...
A consumer products testing group is evaluating two competing brands of tires, Brand 1 and Brand 2. Though the two brands have been comparable in the past, some technological advances were recently made in the Brand 2 manufacturing process, and the consumer group is testing to see if Brand 2 will outperform Brand 1. Tread wear can vary considerably depending on the type of car, and the group is trying to eliminate this effect by installing the two brands on...
A consumer testing agency tested 130 makes and models of cars. In the model below, price...
A consumer testing agency tested 130 makes and models of cars. In the model below, price (in 1000s) was the dependent variable, and the independent variables included miles per gallon (MPG), Handling score (on a scale from 0 to 5) and Reliability score (on a scale from 0 to 20), as well as a dummy, d_Leather, indicating that the car has a leather interior. The residual plot for MPG is also included. SUMMARY OUTPUT Regression Sta tistics Multiple R 0.719064...
ADVERTISEMENT
Subjects
ADVERTISEMENT
Latest Questions
ADVERTISEMENT