In: Statistics and Probability
Construct the 92% confidence interval for mean of following data by assuming that the data follow normal distribution. You have to use 92% Z value.
132, 135, 149, 133, 119, 121, 128, 132, 119, 110, 118, 137, 140, 139, 107, 116, 122, 124, 115, 103
The sample size is n = 20
The provided sample data along with the data required to compute the sample mean Xˉ and sample variance s^2 are
X |
X2 |
|
132 |
17424 |
|
135 |
18225 |
|
149 |
22201 |
|
133 |
17689 |
|
119 |
14161 |
|
121 |
14641 |
|
128 |
16384 |
|
132 |
17424 |
|
119 |
14161 |
|
110 |
12100 |
|
118 |
13924 |
|
137 |
18769 |
|
140 |
19600 |
|
139 |
19321 |
|
107 |
11449 |
|
116 |
13456 |
|
122 |
14884 |
|
124 |
15376 |
|
115 |
13225 |
|
103 |
10609 |
|
Sum = |
2499 |
315023 |
The sample mean Xˉ is computed as follows:
Also, the sample variance s^2 is
Therefore, the sample standard deviation s is
The provided sample mean is Xˉ=124.95
and the sample standard deviation is s = 12.08
The size of the sample is n = 20
and the required confidence level is 92%.
The number of degrees of freedom are df = 20 - 1 = 19
and the significance level is α=0.08.
Based on the provided information, the critical t-value is
t_c = 1.85
The 92% confidence for the population mean μ is computed using the following expression
Therefore, based on the information provided, the 92 % confidence for the population mean μ is
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