Question

Compute the area under y = √x between x = a and x = b where a and b are user specified values obtained via cin. Account for invalid user input cases of a < 0 and a > b. For each case of invalid input, immediately output to the user what the error was. Allow the user a total of three chances to enter valid input for each input request. If the user enters incorrect input three times in a row for an input request, display a different error and exit the program.

Answer 1

#include
#include // std::setprecision
#include
#include
#include // std::string, std::stod
#include
using namespace std;

int main()
{
float a,b;
for(int i=0;i<3;i++)
{
cout<<"Enter a and b"< cin>>a>>b;
if(a>=0&&a<=b)
break;
else
{
if(i==2)
{
cout<<"You have exhausted all 3 chances"< return 1;
}

cout<<"Invalid values entered"< }

}
float b3=b*b*b,a3=a*a*a;
float value=(float)(sqrt((b3))-sqrt(a3));
cout<<"The area computed is equal to : "<<(float)((float)2/(float)3)*(float)value<

}

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