Question

How can you determine if you need to use a combination or permutation to count the number of outcomes? Which will usually have more outcomes? Why? Provide an example in your explanation.

(please provide detailed answer with no less than 100 characters)

Answer 1

.Lf onder does not matteh, tis a combinat ibn phoblem Tt ondeh does aa matt en tis a permutection phoblem. And thert is also di ff errence between how you count aru ond what counting Eample sufese 4 tails 2 heads and WHh this example , t does not seem the dle nok puo he ads o9n tails Com binotion oCcunance mattenS, so are tossing thi same Coin, you can not distinguish betes een Gmilarly 04 cannet thead tails dstinguish betue thu-fouth penmutections would give 0nden does et matte. mone outcone Because H4-4)(u)u= (+45-4) (u) u- wher nP is ton mula fo pemutatt on Pub nCn is tohmula foh com bin ation when fram object n object you ae choosing n obiously from fonmula also permutation is 240u than combination You tahe and choose 2om them titis combinedtion thin then 5 XEXAXS ititis permutection 09=