Question

In: Statistics and Probability

A 2^4-1  experiment was performed to improve the yield of a chemical process. Four factors were selected,...

A 2^4-1  experiment was performed to improve the yield of a chemical process. Four factors were selected, and two replicates were run. Due to raw materials constraints, it was possible to run only 8 runs. Thus, the design generator D = ABC was selected. The data are shown in the following table. Create the standard order fractional factorial design in Minitab. Analyze the fractional factorial design and, following the principle of hierarchical order, remove all interaction terms then main effects that are not statistically significant at p = 0.05. Analyze the reduced factorial design and output a normal probability plot, fitted values plot, and plots of the residuals versus each factor. State the final model and comment on its adequacy based on its R-square values and residuals analyses. What settings of the final model predictors maximize yield?

RUN A B C D YIELD
1 -1 -1 -1 -1 97
2 1 -1 -1 1 74
3 -1 1 -1 1 81
4 1 1 -1 -1 71
5 -1 -1 1 1 92
6 1 -1 1 -1 81
7 -1 1 1 -1 88
8 1 1 1 1 83
9 -1 -1 -1 -1 98
10 1 -1 -1 1 72
11 -1 1 -1 1 87
12 1 1 -1 -1 80
13 -1 -1 1 1 99
14 1 -1 1 -1 79
15 -1 1 1 -1 87
16 1 1 1 1 85

Solutions

Expert Solution

ANSWER:


Factorial Fit: Y versus A, B, C, D

Estimated Effects and Coefficients for Y (coded units)

Term Effect Coef SE Coef T P
Constant 84.625 0.8385 100.92 0.000
A -13.000 -6.500 0.8385 -7.75 0.000
B -3.750 -1.875 0.8385 -2.24 0.056
C 4.250 2.125 0.8385 2.53 0.035
D -1.000 -0.500 0.8385 -0.60 0.567
A*B 7.000 3.500 0.8385 4.17 0.003
A*C 3.500 1.750 0.8385 2.09 0.070
A*D 1.750 0.875 0.8385 1.04 0.327


S = 3.35410 PRESS = 360
R-Sq = 92.21% R-Sq(pred) = 68.85% R-Sq(adj) = 85.40%


Analysis of Variance for Y (coded units)

Source DF Seq SS Adj SS Adj MS F P
Main Effects 4 808.50 808.500 202.125 17.97 0.000
A 1 676.00 676.000 676.000 60.09 0.000
B 1 56.25 56.250 56.250 5.00 0.056
C 1 72.25 72.250 72.250 6.42 0.035
D 1 4.00 4.000 4.000 0.36 0.567
2-Way Interactions 3 257.25 257.250 85.750 7.62 0.010
A*B 1 196.00 196.000 196.000 17.42 0.003
A*C 1 49.00 49.000 49.000 4.36 0.070
A*D 1 12.25 12.250 12.250 1.09 0.327
Residual Error 8 90.00 90.000 11.250
Pure Error 8 90.00 90.000 11.250
Total 15 1155.75

so here at 5% significance AC ,AD, B ,D are having statistically insignificant result( as there p-value >0.05).

also i cannot perform test lefting the effect has no effect as A and C has significant result but AC has insignificant result. so while including A and C i cannot ignore AC.

NOTE:: I hope this answer is helpfull to you......**Please support me with your rating

**Please give me"LIKE".....Its very important for me......THANK YOU


Related Solutions

An experiment was performed to improve the yield of a chemical process. Four factors were selected,...
An experiment was performed to improve the yield of a chemical process. Four factors were selected, and two replicates of a completely randomized experiment were run. Based on the ANOVA table below, determine which factors are important in explaining yield. Use α = 0.05. A B C D AB AC AD BC BD CD ABC ABD ACD BCD ABCD
An experiment was performed to improve the yield of a chemical process. Four factors were selected,...
An experiment was performed to improve the yield of a chemical process. Four factors were selected, and two replicates of a completely randomized experiment were run. The results are shown in the following table: A B C D Yield 1 -1 -1 -1 -1 95 2 -1 -1 -1 -1 93 3 1 -1 -1 -1 74 4 1 -1 -1 -1 78 5 -1 1 -1 -1 81 6 -1 1 -1 -1 85 7 1 1 -1 -1...
1. To study the effect of temperature on yield in a chemical process, five batches were...
1. To study the effect of temperature on yield in a chemical process, five batches were produced at each of three temperature levels. The results follow. Temperature 50°C 60°C 70°C 31 30 24 21 31 29 33 34 29 36 23 31 29 27 32 a. Construct an analysis of variance table (to 2 decimals but p-value to 4 decimals, if necessary). Source of Variation Sum of Squares Degrees of Freedom Mean Square F p-value Treatments 2 0.0 Error 12...
Yield of Chemical Process Two catalysts were analyzed to determine how they affect the mean yield...
Yield of Chemical Process Two catalysts were analyzed to determine how they affect the mean yield of chemical process. Specifically, catalyst 1 is currently used; but catalyst 2 is acceptable. Because catalyst 2 is cheaper, it should be adopted, if it does not change the process yield. Two tests were run in the pilot plant. Eight samples of each type of catalyst were randomly and independently selected from the pilot plant, and the chemical process yield were recorded. The data...
To study the effect of temperature on yield in a chemical process, five batches were produced...
To study the effect of temperature on yield in a chemical process, five batches were produced at each of three temperature levels. The results follow. Temperature 50°C 60°C 70°C 37 35 30 27 36 35 39 39 35 42 28 37 35 32 38 A. Construct an analysis of variance table (to 2 decimals, if necessary). Round p-value to four decimal places. Source of variation sum of squares degrees of freedom mean square F    P- Value Treatments Error Total...
To study the effect of temperature on yield in a chemical process, five batches were produced...
To study the effect of temperature on yield in a chemical process, five batches were produced at each of three temperature levels. The results follow. Temperature 50°C 60°C 70°C 32 34 29 22 35 34 34 38 34 37 27 36 30 31 37 a. Construct an analysis of variance table (to 2 decimals but p-value to 4 decimals, if necessary). Source of Variation Sum of Squares Degrees of Freedom Mean Square F p-value Treatments Error Total b. Use a  level...
To study the effect of temperature on yield in a chemical process, five batches were produced...
To study the effect of temperature on yield in a chemical process, five batches were produced at each of three temperature levels. The results follow. Temperature 50°C 60°C 70°C 32 30 25 22 31 30 34 34 30 37 23 32 30 27 33 a. Construct an analysis of variance table (to 2 decimals but p-value to 4 decimals, if necessary). Source of Variation Sum of Squares Degrees of Freedom Mean Square F p-value Treatments Error Total b. Use a.05...
To study the effect of temperature on yield in a chemical process, five batches were produced...
To study the effect of temperature on yield in a chemical process, five batches were produced at each of three temperature levels. The results follow. Temperature 50°C 60°C 70°C 31 33 23 21 34 28 33 37 28 36 26 30 29 30 31 a. Construct an analysis of variance table (to 2 decimals but p-value to 4 decimals, if necessary). b. Use a level of significance to test whether the temperature level has an effect on the mean yield...
To study the effect of temperature on yield in a chemical process, five batches were produced...
To study the effect of temperature on yield in a chemical process, five batches were produced at each of three temperature levels. The results follow. Temperature 50°C 60°C 70°C 34 28 27 24 29 32 36 32 32 39 21 34 32 25 35 Construct an analysis of variance table (to 2 decimals, if necessary). Round p-value to four decimal places.
To study the effect of temperature on yield in a chemical process, five batches were produced...
To study the effect of temperature on yield in a chemical process, five batches were produced at each of three temperature levels. The results follow. Temperature 50°C 60°C 70°C 30 26 24 20 27 29 32 30 29 35 19 31 28 23 32 a. Construct an analysis of variance table (to 2 decimals but p-value to 4 decimals, if necessary). Source of Variation Sum of Squares Degrees of Freedom Mean Square F p-value Treatments Error Total b. Use a...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT