Question

2. (A) Determine the magnetic force acting on a conducting 10.00cm straight piece of wire with a current of 1.00 A, placed so the wire has the positive current flowing east (electrons in the wire are flowing west, which means the positive current in the wire is flowing [East] (or just [E])) when in an external 0.512 Tesla (T) magnetic field which is also horizontal and pointing 37.5° east of north (i.e. B = 0.512 T [N37.5°E]).

(B) What is the magnetic field strength (in Tesla) created by the wire itself at a distance of 2.00cm away from the wire?

Answer A and B and write clearly please and thank you :)

Answer 1

2) (A)Given the length of the wire = 10cm = 10 x 10-2m, the current flowing through the wire I = 1A towards East and the external magnetic filed is B = 0.512T which is acting 37.5 North of East. The diagram of the situation is given below.

The magnetic force (F) due to a current carrying wire is given by,

So the magnetic force acting on the conductor is 0.031N.

(B) Given the distance from the wire d = 2cm = 2 x 10-2m. The diagram of the situation is shown below.

From the figure,

The magnetic field (B) produced by a current carrying wire itself at a distance d from the centre of a wire of finite length is,

where = permeability of free space = 4 x 10-7NA-2.

So the magnetic field strength created by the wire itself at a distance 2cm from the wire is 9.28 x 10-6T.