Solve Legendre’s equation for the given initial conditions. (1 — х)у -

Solve Legendre’s equation for the given initial conditions. (1 - x2)y - 2xy + 6y = 0

Solutions

Expert Solution

MuPAD can be used to solve both symbolic and numeric types of calculations. MuPAD can be run by entering mupadwelcome in the command window.

To solve a differential equation and get the result in explicit series, the solve function can be used.

To calculate the Legendre\'s equation, enter the following lines in MuPAD:

Define the differential equation:

eqn:=ode({(1-x^2)*y\'\'(x)-2*x*y\'(x)+6*y(x)=0,y(0)=5, y\'(0)=0}, y(x));

Solve the differential equation:

solve(eqn)

The result obtained is:

Define the differential equation:

Solve the differential equation:

MuPAD can be used to solve both symbolic and numeric types of calculations. MuPAD can be run by entering mupadwelcome in the command window.

To solve a differential equation and get the result in explicit series, the solve function can be used.

To calculate the Legendre\'s equation, enter the following lines in MuPAD:

Define the differential equation:

eqn:=ode({(1-x^2)*y\'\'(x)-2*x*y\'(x)+6*y(x)=0,y(0)=5, y\'(0)=0}, y(x));

Solve the differential equation:

solve(eqn)

The result obtained is:

Define the differential equation:

Solve the differential equation:

solve(eqn)

{5 - 15x2}

Thus, the series solution of the given Legendre\'s equation has been calculated.

Junaid answered 1 year ago

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