In: Statistics and Probability
a)
We should have at least 2 elements per groups. Hence we should have 6 * 2 = 12 plants in the study.
Here we used 6, because there are 5 types of fertilizers and one placebo(control) group.
Also, do note that we should have the numbers of elements to be as high as possible for the normality assumptions to be valid.
b)
For the control group, we will not use any fertilizer
c)
We would assign 2 to each 6 groups. Ie 2 to the placebo group and 10 to the five fertilizer groups (2 each)
d)
Null Hypothesis would be that all groups would have same mean
e)
Alternate Hypothesis would be that at least one group is different
f)
We will not give any fertilizer to the control group and one fertilizer each to the remaining five groups.
g)
We would measure the time taken by strawberries to grow from seeds
h)
The confounding variables would be the amount of water given and sunlight. To minimize the impact of these variables we would ensure that water and sunlight are given equally to the six groups.
i)
We would be using one way ANOVA to compare the six groups
j)
If our p value was 0.021, we would reject the null hypothesis as it is less than 0.05 (significance level)
k)
We would do a post hoc test
l)
No, results should not be used for the soil experiment as the fertility of soil will impact the results