Question

In: Statistics and Probability

Let x be the average number of employees in a group health insurance plan, and let...

Let x be the average number of employees in a group health insurance plan, and let y be the average administrative cost as a percentage of claims.

x 3 7 15 38 70
y 40 35 30 26 16

(a) Make a scatter diagram of the data and visualize the line you think best fits the data.


(b) Would you say the correlation is low, moderate, or strong? positive or negative?

low and positive

moderate and positive     

moderate and negative

strong and positive

low and negative

strong and negative


(c) Use a calculator to verify that Σx = 133, Σx2 = 6627, Σy = 147, Σy2 = 4657, and Σxy = 2923. Compute r. (Round your answer to three decimal places.)
r =  

As x increases, does the value of r imply that y should tend to increase or decrease? Explain.

Given our value of r, y should tend to remain constant as x increases.

Given our value of r, y should tend to increase as x increases.     

Given our value of r, we cannot draw any conclusions for the behavior of y as x increases.

Given our value of r, y should tend to decrease as x increases.

Solutions

Expert Solution

a

.

a.

scatter plot shown above

Line of Regression Y on X i.e Y = bo + b1 X
X Y (Xi - Mean)^2 (Yi - Mean)^2 (Xi-Mean)*(Yi-Mean)
3 40 556.96 112.36 -250.16
7 35 384.16 31.36 -109.76
15 30 134.56 0.36 -6.96
38 26 129.96 11.56 -38.76
70 16 1883.56 179.56 -581.56

calculation procedure for regression
mean of X = sum ( X / n ) = 26.6
mean of Y = sum ( Y / n ) = 29.4
sum ( (Xi - Mean)^2 ) = 3089.2
sum ( (Yi - Mean)^2 ) = 335.2
sum ( (Xi-Mean)*(Yi-Mean) ) = -987.2
b1 = sum ( (Xi-Mean)*(Yi-Mean) ) / sum ( (Xi - Mean)^2 )
= -987.2 / 3089.2
= -0.32
bo = sum ( Y / n ) - b1 * sum ( X / n )
bo = 29.4 - -0.32*26.6 = 37.9
value of regression equation is, Y = bo + b1 X
Y'=37.9-0.32* X          

b.

( X) ( Y) X^2 Y^2 X*Y
3 40 9 1600 120
7 35 49 1225 245
15 30 225 900 450
38 26 1444 676 988
70 16 4900 256 1120

calculation procedure for correlation
sum of (x) = 133
sum of (y) = 147
sum of (x^2) = 6627
sum of (y^2) = 4657
sum of (x*y) = 2923
to calculate value of r( x,y) = co variance ( x,y ) / sd (x) * sd (y)
co variance ( x,y ) = [ sum (x*y - N *(sum (x/N) * (sum (y/N) ]/n-1
= 2923 - [ 5 * (133/5) * (147/5) ]/5- 1
= -197.44
and now to calculate r( x,y) = -197.44/ (SQRT(1/5*2923-(1/5*133)^2) ) * ( SQRT(1/5*2923-(1/5*147)^2)
=-197.44 / (24.856*8.188)
=-0.97
value of correlation is =-0.97
coefficient of determination = r^2 = 0.941
properties of correlation
1. If r = 1 Correlation is called Perfect Positive Correlation
2. If r = -1 Correlation is called Perfect Negative Correlation
3. If r = 0 Correlation is called Zero Correlation
& with above we conclude that correlation ( r ) is = -0.9701< 0, perfect negative correlation          

low and negative   

c.

value of correlation is =-0.97
coefficient of determination = r^2 = 0.941

As X increases then r ,y values also increases


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