Question

write a program that gets four digits from the user and tests to see which digit is the biggest and which is the smallest, use single-alternative only

sample output is below:

enter four digits and i will tell you which is biggest and smallest:

4 6 7 9

the biggest is 9

the smallest is 4

Answer 1

PROGRAM IS DONE WITH C++ LANGUAGE.

IT IS TESTED IN DEV-C++ 5.11 SOFTWARE AND IS GIVING CORRECT OUTPUT.

PROGRAM IS DONE IN TWO WAYS

PROGRAM 1. TAKE INDIVIDUAL 4 DIGITS FROM USER AND FIND MAX AND MIN FROM THEM.

PROGRAM 2. TAKE 4 DIGITS IN NUMBER FORMAT, FROM USER THEN FIND THE MAX AND MIN DIGITS FROM THEM.

PROGRAM 1

#include<iostream>
using namespace std;
int main()
{
   int dig[4],i;
   int max=0,min;
   /* enter 4 digits */
   cout<<"enter four digits" <<endl;
   for(i=0;i<4;i++)
   {
       cin>>dig[i];
   }
   /* calculate max value */
   for(i=0;i<4;i++)
   {
       if(dig[i]>max)
       {
           max=dig[i];
       }
   }
   min=dig[0];
   /* calculate min value */
   for(i=0;i<4;i++)
   {
       if(min>dig[i])
       {
           min=dig[i];
       }
   }
   /* print max and min value */
   cout<<endl<<"the biggest is " <<max;
   cout<<endl<<"the smallest is "<<min;
   return 0;
}

SCREEN SHOT

OUTPUT

PROGRAM 2

#include<iostream>
using namespace std;
int main()
{
   int dig[4],i,n;
   int max=0,min;
   i=0;
   /* enter 4 digit number */
   cout<<"enter a number of 4 digits :";
   cin>>n;
   /* while loop will run until n is zero */
   while(n!=0)
   {
       /* take digits in array */
       dig[i]= n%10;
       n=n/10;
       i++;
   }
   /* calculate max value */
   for(i=0;i<4;i++)
   {
       if(dig[i]>max)
       {
           max=dig[i];
       }
   }
   min=dig[0];
   /* calculate min value */
   for(i=0;i<4;i++)
   {
       if(min>dig[i])
       {
           min=dig[i];
       }
   }
   /* print max and min value */
   cout<<endl<<"the biggest is " <<max;
   cout<<endl<<"the smallest is "<<min;
   return 0;
}

SCREEN SHOT

OUTPUT