In: Statistics and Probability
Answer :
Given data is :
Sample size n = 89
| A | B | C | D | 
| 23 | 22 | 34 | 10 | 
Based on these,
Null hypothesis 
 is :
Correct answers for all multiple choice questions are evenly
distributed.
Alternative hypothesis 
 is ;
Correct answers for all multiple choice questions are evenly
distributed.
Now,
| Choice | Probability (P) | 
 Observed (O)  | 
 Expected value (E) E = n * p  | 
![]()  | 
| A | 1 / 4 = 0.25 | 23 | 
 = 89 * 0.25 = 22.25  | 
 =  =  = =0.0253  | 
| B | 1 / 4 = 0.25 | 22 | 22.25 | 0.0028 | 
| C | 1 / 4 = 0.25 | 34 | 22.25 | 6.205 | 
| D | 1 / 4 = 0.25 | 10 | 22.25 | 6.744 | 
| 
 = 23 + 22 + 34 +10 = 89  | 
 
 = 0.0253 + 0.0028 + 6.205 + 6.744 = 12.977  | 
a)Test statistics 
 = 12.977
b)Given significance level 
Degree of freedom df = n - 1 = 4 - 1 = 3,
So critical value form chi square table is ;
Critical value = 6.251.
We get Critcal value < test statistics.
c)YES
We have sufficient evidence to support the claim.