In: Economics
Consider an EOY geometric gradient, which lasts for eight years, whose initial value
at EOY one is $4000 and g = 6% per year thereafter. For an equivalent cash flow, find the
equivalent uniform gradient amount, G over the same period if the initial value of the cash flows
at the end of year one is $(3000). The interest rate is 18% per year. draw the cash flow diagram.
Rate of Interest = 18%
g = 6% which means cash flow increases by 6% every year
Present value if calculated as [Gradient cash flow / (1 + Rate of Interest)^Year]
| Year | Gradient Cash Flow | Present Value | 
| 1 | 4,000.00 | 3,389.83 | 
| 2 | 4,240.00 | 3,045.10 | 
| 3 | 4,494.40 | 2,735.43 | 
| 4 | 4,764.06 | 2,457.25 | 
| 5 | 5,049.91 | 2,207.36 | 
| 6 | 5,352.90 | 1,982.88 | 
| 7 | 5,674.08 | 1,781.23 | 
| 8 | 6,014.52 | 1,600.09 | 
| 19,199.19 | 
Uniform payment would be same for all 8 periods while there is uniform gradient amount which means cash flow rises by fixed amount every year
| Year | Uniform payment | Present value of uniform payment | Increased amount | Present value of Increased Amount | 
| 1 | 3,000.00 | 2,542.37 | - | - | 
| 2 | 3,000.00 | 2,154.55 | 1X | 0.72X | 
| 3 | 3,000.00 | 1,825.89 | 2X | 1.22X | 
| 4 | 3,000.00 | 1,547.37 | 3X | 1.55X | 
| 5 | 3,000.00 | 1,311.33 | 4X | 1.75X | 
| 6 | 3,000.00 | 1,111.29 | 5X | 1.85X | 
| 7 | 3,000.00 | 941.78 | 6X | 1.88X | 
| 8 | 3,000.00 | 798.11 | 7X | 1.86X | 
| 12,232.70 | 10.83X | 
To make both of these cash flow equivlent, present value of both of them should be equal to each other.
12,232.70 + 10.83X = 19,199.19
X = 643.25
Thus, fixed increased of amount should be 643.25
