In: Economics
Consider an EOY geometric gradient, which lasts for eight years, whose initial value
at EOY one is $4000 and g = 6% per year thereafter. For an equivalent cash flow, find the
equivalent uniform gradient amount, G over the same period if the initial value of the cash flows
at the end of year one is $(3000). The interest rate is 18% per year. draw the cash flow diagram.
Rate of Interest = 18%
g = 6% which means cash flow increases by 6% every year
Present value if calculated as [Gradient cash flow / (1 + Rate of Interest)^Year]
Year | Gradient Cash Flow | Present Value |
1 | 4,000.00 | 3,389.83 |
2 | 4,240.00 | 3,045.10 |
3 | 4,494.40 | 2,735.43 |
4 | 4,764.06 | 2,457.25 |
5 | 5,049.91 | 2,207.36 |
6 | 5,352.90 | 1,982.88 |
7 | 5,674.08 | 1,781.23 |
8 | 6,014.52 | 1,600.09 |
19,199.19 |
Uniform payment would be same for all 8 periods while there is uniform gradient amount which means cash flow rises by fixed amount every year
Year | Uniform payment | Present value of uniform payment | Increased amount | Present value of Increased Amount |
1 | 3,000.00 | 2,542.37 | - | - |
2 | 3,000.00 | 2,154.55 | 1X | 0.72X |
3 | 3,000.00 | 1,825.89 | 2X | 1.22X |
4 | 3,000.00 | 1,547.37 | 3X | 1.55X |
5 | 3,000.00 | 1,311.33 | 4X | 1.75X |
6 | 3,000.00 | 1,111.29 | 5X | 1.85X |
7 | 3,000.00 | 941.78 | 6X | 1.88X |
8 | 3,000.00 | 798.11 | 7X | 1.86X |
12,232.70 | 10.83X |
To make both of these cash flow equivlent, present value of both of them should be equal to each other.
12,232.70 + 10.83X = 19,199.19
X = 643.25
Thus, fixed increased of amount should be 643.25