In: Statistics and Probability
Eight runners were convinced that the average difference in their individual times for running one mile versus race walking one mile was at most 2 minutes. Below are their times. Do you agree that the average difference is at most 2 minutes? Conduct a hypothesis test at the 5% level.
Running time (minutes) | Race walking time (minutes) |
5.3 | 7.5 |
5.7 | 9.5 |
6.2 | 10.2 |
4.8 | 6.9 |
7.1 | 8.9 |
4.2 | 9.5 |
6.1 | 9.4 |
4.4 | 7.9 |
NOTE: If you are using a Student's t-distribution for the problem, including for paired data, you may assume that the underlying population is normally distributed. (In general, you must first prove that assumption, though.)
1) State the distribution to use for the test. (Enter your answer in the form z or tdf where df is the degrees of freedom.)
2) What is the test statistic? (If using the z distribution round your answer to two decimal places, and if using the t distribution round your answer to three decimal places.)
3) What is the p-value? (Round your answer to four decimal places.)
4) Alpha (Enter an exact number as an integer, fraction, or
decimal.)
α =
1)
Here we have paired data so paired t test will be used.
Let d =Race walking time-Running time
Following table shows the calculations:
Race walking time | Running time | d | (d-mean)^2 |
7.5 | 5.3 | 2.2 | 1.1025 |
9.5 | 5.7 | 3.8 | 0.3025 |
10.2 | 6.2 | 4 | 0.5625 |
6.9 | 4.8 | 2.1 | 1.3225 |
8.9 | 7.1 | 1.8 | 2.1025 |
9.5 | 4.2 | 5.3 | 4.2025 |
9.4 | 6.1 | 3.3 | 0.0025 |
7.9 | 4.4 | 3.5 | 0.0625 |
Total | 26 | 9.66 |
2)
3)
4)
α = 0.05
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