Question

In: Economics

For this? problem, use the fact that the expected value of an event is a probability...

For this? problem, use the fact that the expected value of an event is a probability weighted? average, the sum of each probable outcome multiplied by the probability of the event occurring. You own a house worth ?$800, 000 that is located on a river. If the river floods? moderately, the house will be completely destroyed. This happens about once every 20 years. If you build a? seawall, the river would have to flood heavily to destroy your? house, which only happens about once every 200 years. What would be the annual premium without a seawall for an insurance policy that offers full? insurance? Without a? seawall, the annual premium is ?$ 40000. ?(Round your response to the nearest whole? number.) What would be the annual premium with a seawall for an insurance policy that offers full? insurance? With a? seawall, the annual premium is ?$ 4000. ?(Round your response to the nearest whole? number.)

***For a policy that only pays 75?% of the home? value, what are your expected costs without a? seawall? Without a? seawall, the expected cost is ?$ nothing. ?(Round your response to the nearest whole? number.)

Solutions

Expert Solution

Solution

Step (1)

Refer to the following table that lists the expected values of the house that remains W flood with and without a seawall:

Step (2)

The expected values are calculated by multiplying the chances of each event occurring (heavy or moderate flooding) by the value of the house if that respective event were to take place. Take the cell in red for example. The chances of a moderate flood occurring are 0.02. When this happens and there is no seawall built, the value of the house is reduced to $0 because it will be completely destroyed. The remaining 0.98 probability indicates the changes of a moderate flood not occurring, during which the house will retain its full value of $800,000 because it remains standing. Therefore, the expected value of the house is $784,000 when there is a moderate flood and no seawall is built.

Step (3)

Refer to the cells in blue. When there is a heavy flood, the value of the house will be reduced to SO regardless if there is a seawall built because the wall cannot withstand the flood. That is why there is a 100% (or 1.00) chance that the house's value will drop to $0. Conversely, there is a 0% chance that the house will retain its value of $800,000 when a heavy flood occurs.

Step (4)

Refer to the cell green. When there is a moderate flood, the value of the house will remain at $800,000 when there is a seawall built because it protects against the flood. Therefore, there is a 0% chance that the value of the house will drop to $o. Conversely, there is a 100% chance that the house will retain its full value.

Step (5)

The expected costs of each event occurring given that you did and did not build a seawall is calculated as the loss in the expected value of your house. Since your house is worth originally worth $800,000, we can find the expected costs with and without a seawall follows by taking the difference between $800,000 and the house's expected value at each instance as follows:

The expected Costs and without a sea well is calculated above:

Step (6)

There is not enough information provided regarding the pricing of annual premiums for the house. We cannot find the cost of an insurance policy that offers full insurance nor a policy that pays only 75% of the home value. However, different policies should provide an incentive to be safer because if you knew that you would only receive a payment worth 75% of your house ($800,000.0.75 = $600,000) rather than a full payment of $800,000, you would be more careful in protecting your house against possible floods to minimize your expected costs.


Related Solutions

For this problem, use the fact that the expected value of an event is a probability...
For this problem, use the fact that the expected value of an event is a probability weighted? average, the sum of each probable outcome multiplied by the probability of the event occurring. You own a house worth $400,000 that is located on a river. If the river floods? moderately, the house will be completely destroyed. This happens about once every 50 years. If you build a seawall, the river would have to flood heavily to destroy your house, which only...
6. For this problem we will use the fact that: ?????? = ??????? − ???? ?...
6. For this problem we will use the fact that: ?????? = ??????? − ???? ? ? = ? ? − ?(?) A company produces and sells copies of an accounting program for home computers. The total weekly cost (in dollars) to produce x copies of the program is ? ? = 8? + 500, and the weekly revenue for selling all x copies of the program is ? ? = 35? − 0.1?). a. Find a function, ?(?), for...
1. The probability of event A is 60%, the probability of event B is 40%, and...
1. The probability of event A is 60%, the probability of event B is 40%, and the probability of either A or B is 65%. What is the probability of events A and B simutaneously? 2. 50% of items are Type A, 30% are Type B, and 20% are Type C. each type is broken up into V1 and V2. Type A is 80% V1, Type B is 60% V1, and Type C is 30% V1. If a randomly selected...
In probability theory, a conditional probability measures the probability of an event given another event has...
In probability theory, a conditional probability measures the probability of an event given another event has occurred. The conditional probability of A given B, denoted by P(A|B), is defined by P(A|B) = P(A ∩ B) P(B) , provided P(B) > 0. Show that the conditional probability defined above is a probability set function. That is show that a) P(A|B) ≥ 0 [4 Marks] b) P(S|B) = 1. [4 Marks] c) P( S Ai |B) = PP(Ai |B) [4 Marks]
To work this problem, use the fact that the image formed by the first surface becomes...
To work this problem, use the fact that the image formed by the first surface becomes the object for the second surface. The figure below shows a piece of glass with index of refraction n = 1.50 surrounded by air. The ends are hemispheres with radii R1 = 2.00 cm and R2 = 4.00 cm, and the centers of the hemispherical ends are separated by a distance of d = 7.48 cm. A point object is in air, a distance...
The probability of success in Bernoulli is 0.7. Find the expected value and variance of the...
The probability of success in Bernoulli is 0.7. Find the expected value and variance of the number of failures until the ninth success. (The problem is to find the mean and variance of the number of failures in the negative binomial distribution given the Bernoulli probability of success.)
Use the fact that the present value of a perpetuity paying $X per period starting in...
Use the fact that the present value of a perpetuity paying $X per period starting in one year is X/r, where r is the riskless rate of return, to determine the present value of annual payments of $X accruing for 20 years, starting one year from now. Hint: Think of it as a perpetuity less the appropriately discounted value of a perpetuity starting 20 years from now.
Give the expected value, variance, and probability distribution for the sum of a fair coin and...
Give the expected value, variance, and probability distribution for the sum of a fair coin and a random real number chosen uniformly in the range [ -1, 1]. Sketch the PMF.
4.  Problem 8.06 (Expected Returns) Stocks A and B have the following probability distributions of expected future...
4.  Problem 8.06 (Expected Returns) Stocks A and B have the following probability distributions of expected future returns: Probability     A     B 0.1 (5 %) (38 %) 0.2 5 0 0.5 10 24 0.1 22 26 0.1 37 49 Calculate the expected rate of return, , for Stock B ( = 11.40%.) Do not round intermediate calculations. Round your answer to two decimal places.   % Calculate the standard deviation of expected returns, σA, for Stock A (σB = 22.22%.) Do not round...
Problem 8-6 Expected returns Stocks A and B have the following probability distributions of expected future...
Problem 8-6 Expected returns Stocks A and B have the following probability distributions of expected future returns: Probability A B 0.1 -10% -29% 0.2 6 0 0.4 10 24 0.2 18 28 0.1 30 37 Calculate the expected rate of return, rB, for Stock B (rA = 10.80%.) Do not round intermediate calculations. Round your answer to two decimal places. % Calculate the standard deviation of expected returns, σA, for Stock A (σB = 18.77%.) Do not round intermediate calculations....
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT