In: Statistics and Probability
A clinical trial evaluates a new compound designed to improve wound healing in trauma patients. The new compound is compared against a placebo. After treatment for 5 days with the new compound or placebo, the extent of wound healing is measured and the data are shown in table 7-51. Is there a difference in the extent of wound healing by treatment? Run the appropriate test at a 5% level of significance. (Hint : Are treatment and the percent of wound healing independent?
The Chi-Square test of independence is used to determine if there is a significant relationship between two factors.
For variables % Wound Healing and Treatment ,
The Chi-Square test of independence is performed in following steps,
Step 1: The hypothesis is defined as,
Null hypothesis, Ho:There is no association between two variables.
Alternative hypothesis, Ha There is an association present between the two variables.
Step 2: The significance level for the test is,
Step 3: The Chi-Square test statistic is obtained as follow,
The observed values are,
Obsserved values | |||||
% Wound Healing | |||||
0-25% | 26-50% | 51-75% | 76-100% | Total | |
New Compound | 15 | 37 | 32 | 41 | 125 |
Placebo | 36 | 45 | 34 | 10 | 125 |
Total | 51 | 82 | 66 | 51 | 250 |
Step 4: The expected values are obtained using the formula,
The expected values are,
Expected values | |||||
% Wound Healing | |||||
0-25% | 26-50% | 51-75% | 76-100% | Total | |
New Compound | 25.5 | 41 | 33 | 25.5 | 125 |
Placebo | 25.5 | 41 | 33 | 25.5 | 125 |
Total | 51 | 82 | 66 | 51 | 250 |
Step 5: Now the Chi-Square Value is obtained using the formula,
Step 4: The P-value for Chi-Square statistic is obtained using the chi square distribution table,
Step 5:
The null hypothesis is rejected. It can be stated now, the two variables are dependent. There is a statistically significant association between two variables % Wound Healing and Treatment.