In: Physics
Consider an RC circuit with E = 12.0 V ,R = 165 Ω , and C = 55.6 μF .
A) Find the time constant for the circuit.
B) Find the maximum charge on the capacitor.
C) Find the initial current in the circuit.
For RC circuit, we have given that :
voltage of the battery, = V = 12 V
resistance, R = 165
capacitance, C = 55.6 x 10-6 F
(A) the time constant for the circuit is given as :
= RC { eq.1 }
inserting the values in above eq.
= (165 ) (55.6 x 10-6 F)
= 9174 x 10-6 sec
= 9.17 x 10-3 sec
Or = 9.17 ms
(B) the maximum charge on the capacitor is given as :
Qmax = C V { eq.2 }
inserting the values in eq.2,
Qmax = (55.6 x 10-6 F) (12 V)
Qmax = 667.2 x 10-6 C
Qmax = 667.2 C
(C) the initial current in the circuit which is given as :
using an ohms law, V = I R
or I = V / R { eq.3 }
inserting the values in eq.3,
I = (12 V) / (165 )
I = 0.0727 A
I = 72.7 x 10-3 A
Or I = 72.7 mA