In: Statistics and Probability
With double-digit annual percentage increases in the cost of
health insurance, more and more workers are likely to lack health
insurance coverage (USA Today, January 23, 2004). The
following sample data provide a comparison of workers with and
without health insurance coverage for small, medium, and large
companies. For the purposes of this study, small companies are
companies that have fewer than 100 employees. Medium companies have
100 to 999 employees, and large companies have 1000 or more
employees. Sample data are reported for 50 employees of small
companies, 75 employees of medium companies, and 100 employees of
large companies.
Size of Company | Yes | No | Total | ||
Small | 39 | 11 | 50 | ||
Medium | 69 | 6 | 75 | ||
Large | 90 | 10 | 100 |
1. Compute the X2 test statistic:
2. What is the P-Value? (Using a Chi-Square table)
3.What can we conclude?
4. The USA Today article indicated employees of small
companies are more likely to lack health insurance coverage.
Calculate the percentages of employees without health insurance
based on company size (to the nearest whole number).
Small | % |
Medium | % |
Large | % |
5. Based on the Calculated percentages, what can we conclude?
#1.
Observed | |||
Yes | No | total | |
Small | 39 | 11 | 50 |
Medium | 69 | 6 | 75 |
Large | 90 | 10 | 100 |
Total | 198 | 27 | 225 |
Expected value = sum(coli)*sum(rowi)/total
Expected | ||
Yes | No | |
Small | 44.000 | 6.000 |
Medium | 66.000 | 9.000 |
Large | 88.000 | 12.000 |
Test statistic, chi-square = sum((Oi - Ei)^2/Ei) = 6.25
#2.
p-value = 0.0439
#3.
As p-value < 0.05, reject H0
There are significant evidence to conclude that the size of the organisation and health insurance are not independent
#4.
Small = 22.00%
Medium = 8.00%
Large = 10.00%