In: Physics
Initial height yi=4.0m
The banana was thrown horizontal, initial horizontal velocity of the banana is vix=8.0m/s
Initial vertical velocity is zero viy=0
Vertical acceleration of banana is ay=-9.8m/s2
The vertical acceleration of the banana is constant, the vertical motion of the banana is governed by the kinematics equation for uniformly accelerated motion. To find the time in which the banana covers distance h we use
We want to find the time in which the banana reaches ground y=0.
Horizontal acceleration of the banana is zero, ax=0.
Horizontal velocity of the banana does not change with time
Horizontal distance covered by the banana before it reaches the ground is