Question

In: Statistics and Probability

In a test of the effectiveness of garlic for lowering​ cholesterol, 49 subjects were treated with...

In a test of the effectiveness of garlic for lowering​ cholesterol, 49 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment. The changes​ (before minus​ after) in their levels of LDL cholesterol​ (in mg/dL) have a mean of 0.6 and a standard deviation of 18.1. Use a 0.01 significance level to test the claim that with garlic​ treatment, the mean change in LDL cholesterol is greater than 0. What do the results suggest about the effectiveness of the garlic​ treatment? Assume that a simple random sample has been selected. Identify the null and alternative​ hypotheses, test​ statistic, P-value, and state the final conclusion that addresses the original claim. What are the null and alternative​ hypotheses? A. Upper H 0​: muequals0 ​mg/dL Upper H 1​: mugreater than0 ​mg/dL B. Upper H 0​: muequals0 ​mg/dL Upper H 1​: munot equals0 ​mg/dL C. Upper H 0​: muequals0 ​mg/dL Upper H 1​: muless than0 ​mg/dL D. Upper H 0​: mugreater than0 ​mg/dL Upper H 1​: muless than0 ​mg/dL Determine the test statistic. nothing ​(Round to two decimal places as​ needed.) Determine the​ P-value. nothing ​(Round to three decimal places as​ needed.) State the final conclusion that addresses the original claim. ▼ Reject Fail to reject Upper H 0. There is ▼ not sufficient sufficient evidence to conclude that the mean of the population of changes ▼ equal to is not is greater than is less than 0.

Solutions

Expert Solution

Let denotes the  mean change in LDL cholesterol.

Final conclusion :

There is not sufficient evidence to conclude that the mean of the population of changes is greater than 0.


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