In: Statistics and Probability
You predict that nature reserves located far from large cities (with populations >100,000) have a higher proportion of plant species that are native to their region than reserves that are close to large cities. You collect the following data on 7 nature reserves:
Conduct an appropriate analysis to test the prediction.
using excel>data >data ananlysis> Regression
SUMMARY OUTPUT | ||||||
Regression Statistics | ||||||
Multiple R | 0.032111 | |||||
R Square | 0.001031 | |||||
Adjusted R Square | -0.19876 | |||||
Standard Error | 18.62063 | |||||
Observations | 7 | |||||
ANOVA | ||||||
df | SS | MS | F | Significance F | ||
Regression | 1 | 1.789428 | 1.789428 | 0.005161 | 0.945515 | |
Residual | 5 | 1733.639 | 346.7278 | |||
Total | 6 | 1735.429 | ||||
Coefficients | Standard Error | t Stat | P-value | Lower 95% | Upper 95% | |
Intercept | 74.81957 | 14.30537 | 5.230173 | 0.003381 | 38.04644 | 111.5927 |
distance | 0.019572 | 0.272439 | 0.071839 | 0.945515 | -0.68076 | 0.719899 |
p value of f stat is 0.9455 which is greater tha 0.05 so we conclude that this model is not good to predict the %native
since the data contains oy=utlier which can be easily seen from the scatterplot given so we willl delete the outlier and
using excel>data>data analysis>Regression
Regression Statistics | ||||||
Multiple R | 0.874232 | |||||
R Square | 0.764282 | |||||
Adjusted R Square | 0.705353 | |||||
Standard Error | 3.817751 | |||||
Observations | 6 | |||||
ANOVA | ||||||
df | SS | MS | F | Significance F | ||
Regression | 1 | 189.0324 | 189.0324 | 12.96944 | 0.022732 | |
Residual | 4 | 58.30088 | 14.57522 | |||
Total | 5 | 247.3333 | ||||
Coefficients | Standard Error | t Stat | P-value | Lower 95% | Upper 95% | |
Intercept | 72.69027 | 2.939719 | 24.72695 | 1.59E-05 | 64.5283 | 80.85223 |
distance | 0.211209 | 0.058648 | 3.601311 | 0.022732 | 0.048377 | 0.374042 |
the best regression equation to predit the % native
%native = 72.69v +0.211*distnace
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