In: Statistics and Probability
Suppose you are thinking about getting a puppy and want to know the amount of time people spend caring for puppies. You survey 31 puppy owners and find that the mean amount of time they spend caring for their puppies is 108.0 minutes per day with a sample standard deviation of 17 minutes. Construct a 98% confidence interval for the mean amount of time puppy owners spend on their puppy per day. Interpret the interval. (1pt)
Point Estimate: ______
Margin of Error: ________
Confidence Interval:__________
Interpretation
Solution :
Given that,
= 108.0
s = 17
n =31 Degrees of freedom = df = n - 1 =31 - 1 =30
At 98% confidence level the t is
= 1 - 98% = 1 - 0.98 = 0.02
/ 2 = 0.02/ 2 = 0.01
t /2,df = t0.01,30 =2.457 ( using student t table)
Margin of error = E = t /2 ,df * (s /n)
= 2.457 * ( 17/ 31)
= 7.5019
The 98% confidence interval estimate of the population mean is,
- E < < + E
108.0 - 7.5019< < 108.0+ 7.5019
100.4981 < < 115.5019
(100.4981 , 115.5019 )
The 98% confidence interval estimate of the population mean is,(100.4981 , 115.5019 )
point estimate = 108.0