In: Statistics and Probability
1.
Anystate Auto Insurance Company took a random sample of 388
insurance claims paid out during a 1-year period. The average claim
paid was $1585. Assume σ = $238.
Find a 0.90 confidence interval for the mean claim payment. (Round
your answers to two decimal places.)
lower limit | $ |
upper limit | $ |
Find a 0.99 confidence interval for the mean claim payment. (Round
your answers to two decimal places.)
lower limit | $ |
upper limit | $ |
2.The method of tree ring dating gave the following years A.D. for an archaeological excavation site. Assume that the population of x values has an approximately normal distribution.
1278 | 1257 | 1313 | 1201 | 1268 | 1316 | 1275 | 1317 | 1275 |
(a) find the sample mean year x and sample standard deviation s. (Round your answers to the nearest whole number.)
(b) Find a 90% confidence interval for the mean of all tree ring
dates from this archaeological site. (Round your answers to the
nearest whole number.)
lower limit | A.D. |
upper limit | A.D. |
Solution :
1(a) The 0.90 confidence interval for population mean is given as follows :
Where, x̄ is sample mean, σ is population standard deviation, n is sample size and Z(0.10/2) is critical z-value to construct 0.90 confidence interval.
We have, x̄ = $1585, σ = $238 and n = 388
Using Z-table we get, Z(0.10/2) = 1.6449
Hence, 0.90 confidence interval for the mean claim payment is,
The 0.90 confidence interval for the mean claim payment is ($1565.13, $1604.87).
Lower limit : $1565.13
Upper limit : $1604.87
1(b) The 0.99 confidence interval for population mean is given as follows :
Where, x̄ is sample mean, σ is population standard deviation, n is sample size and Z(0.01/2) is critical z-value to construct 0.99 confidence interval.
We have, x̄ = $1585, σ = $238 and n = 388
Using Z-table we get, Z(0.01/2) = 2.576
Hence, 0.99 confidence interval for the mean claim payment is,
The 0.99 confidence interval for the mean claim payment is ($1553.88, $1616.12).
Lower limit : $1553.88
Upper limit : $1616.12